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max2010maxim [7]
3 years ago
12

Find the gravitational potential energy of a light that has a mass of 13.0 kg and is 4.8 m above the ground

Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

611.52 <---- Is your answer

Explanation:

If you need explanation mark me as brain list

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A length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
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The equivalent resistance of resistors connected in parallel is
\frac{1}{R_{eq}} = \frac{1}{R_1} +  \frac{1}{R_2} + ...
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The problem also says that the equivalent resistance is R_{eq}= 17 \Omega, so we can find the resistance R of each piece of wire:
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In the initial wire, it's like the 5 pieces are connected in series, so the equivalent resistance of the wire is just the sum of the resistances of the 5 pieces:
R_{wire} = 5 R = 5 \cdot 85 \Omega = 425 \Omega
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