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MaRussiya [10]
4 years ago
12

If an electric current of 8.50 A flows for 3.75 hours through an electrolytic cell containing copper-sulfate (CuSO4) solution, t

hen how much copper is deposited on the cathode (the negative electrode) of the cell? (Copper ions carry two units of positive elementary charge, and the atomic mass of copper is 63.5 g/mol.)
Physics
2 answers:
muminat4 years ago
7 0

Answer:

75.5g

Explanation:

From the ionic equation, we can write

CU^{2+}+SO^{2-}_{4}\\

next we find the number of charge

Note Q=it

for i=8.5A, t=3.75 to secs 3.75*60*60=13500secs

hence

Q=8.5*13500\\Q=114750C

Since one faraday represent one mole of electron which equal 96500C

Hence the number of mole produced by 114750C is

114750/96500=1.2mol

The mass of copper produced is

mol=\frac{mass}{molar mass} \\mass=mole*molar mass\\mass=1.2*63.5\\mass=75.5g

Hence the amount of copper produced is 75.5g

Ann [662]4 years ago
5 0

Answer:

75.5 g.

Explanation:

Dissociation equation:

Cu2+ + SO4^2- --> CuSO4

Q = I * t

Where,

I = current

= 8.5 A

t = time

= 3.75 hours

= 13500 s

Q = 8.5 * 13500

= 114750 C

1 faraday represent one mole of electron which equal 96500C

Number of mole of Cu2+

= 114750/96500

= 1.19 mol.

Mass = number of moles * molar mass

= 1.19 * 63.5

= 75.5 g.

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A. acceleration.

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4 years ago
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Unpolarized light is passed through three successive polaroid filters, each with its transmission axis at 32. 8° to the precedin
Oliga [24]

The percentage of light gets through three successive polarized filters is 24.9 %

From the question,

Given that,

Angle of transmission axis = 32.8°

The intensity of light emerging from the first polarizer is determined by the equation

I₁ = I₀ / 2

where I₀ ⇒ intensity of unpolarized light

The light emerging from the second polarizer can be mathematically represented by,

I₂ = I₁ x cos²θ

Substituting the values,

I₂ =( I₀/2) x cos²θ

  = (I₀/2) x cos² (32.8 )

  = (I₀/2) x 0.706

  = (0.706 / 2 ) x I₀

The light emerging from the third polarizer is represented as,

I₃ = I₂ x cos²θ

Substituting the values in the above equation,

I₃ = ( 0.706 / 2 ) I₀ x cos² (32.8)

  = (0.706 / 2 ) I₀ x 0.706

  = 0.249 I₀

The percentage of intensity of light  that gwts through with respect to the intensity of unpolarized light is given by the equation,

(I₃ / I₀) x 100

Substituting the values

[(0.249 x I₀) / I₀ ] x 100 = 24.9 %

Hence the percentage of light gets through is 24.9%

To learn more about unpolarized light: brainly.com/question/17164167

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6 0
2 years ago
Why do we charge a capacitor under a DC voltage source only?
Anit [1.1K]
Because there is always risk of death
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3 years ago
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Look at the diagram showing resistance and flow of electrons.
poizon [28]

The answer would be:

D.

X: Low potential energy

Y: High Potential energy

Z: Flow of electrons

Z is clearly the flow of electrons, as shown by the arrow demonstrating the direction of the flow. So you can easily cross out choices B and C. Now, you can see that Y has more energy stored and X has a lot less, so you can conclude that Y has high potential energy while X has low potential energy.


8 0
3 years ago
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How high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside?
pashok25 [27]

Answer:

15 m

Explanation:

Given,

Mass ( m ) = 75 kg

Potential energy ( P.E ) = 11,025 J

To find : Hight ( h )

Formula : -

P.E = mgh

[ Note : The value of g = 9.8 m/s² ]

h = P.E / mg

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h = 15 m

Hence,

15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.

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2 years ago
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