To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

Here
= True Weight
= Apparent Weight
= Buoyant Force
If we seek to find the apparent weight we will have to,


Remember that
V = Volume (Volume Sphere)
= Density (At this case water density)
g = Gravitational acceleration


Therefore the apparent weight will be 0.1526N
Gravitational force on a satellite is given by the formula

now here we know that force on the satellite is F when its distance from center of Earth is R
Now the distance from the center of earth will be 3R so the force is given as


so if we compare it with initial value of force then it is

so correct answer is

Answer: Varying amounts of the Moon's lit surface being visible from Earth.
Explanation:
Phases of the moon can be defined as the different shapes of the moon visible from the Earth. This happens because sun lits up the face of moon and due to different position of moon in the orbit around earth, varying portion of the lit surface of the moon is visible from Earth. Refer to the diagram below:
D
Because the rest of the answers are illogical
Answer:
The parametric equation for the position of the particle is
.
Explanation:
Given that,
The point is

Time t = 3
Velocity 
We need to calculate the parametric equation for the position of the particle
Using parametric equation for position
....(I)
at t = 3,

Put the value into the formula



Put the value of r₀ in equation (I)


Hence, The parametric equation for the position of the particle is
.