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inn [45]
3 years ago
9

Why does the sun have less gravitational pull on planet far away like Pluto?

Physics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

Because the planet is far away from the sun

Explanation:

The closer the planet is to the Sun, the greater the pull of the Sun's gravity, and the faster the planet orbits.

While, over here the Pluto is very far away from the Sun so it will have very little gravitational  pull and still keeps revolving around the Sun

<h2><u><em>Pls Mark Brainliest</em></u></h2>
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A small metal sphere weighs .28 N in air and has a volume of13
Ray Of Light [21]

To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

W_T = W_A + F_B

Here

W_T= True Weight

W_A= Apparent Weight

F_B= Buoyant Force

If we seek to find the apparent weight we will have to,

W_A = W_T-F_B

W_A = 0.28N - V\rho g

Remember that

V = Volume (Volume Sphere)

\rho= Density (At this case water density)

g = Gravitational acceleration

W_A = 0.28N - (13*10^{-6}m^3)(1000kg/m^3)(9.8)

W_A = 0.1526N

Therefore the apparent weight will be 0.1526N

5 0
4 years ago
When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati
Lubov Fominskaja [6]

Gravitational force on a satellite is given by the formula

F = \frac{GMm}{r^2}

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

F' = \frac{GMm}{(3R)^2}

F' = \frac{GMm}{9R^2}

so if we compare it with initial value of force then it is

F' = \frac{F}{9}

so correct answer is

(1) F/9

7 0
3 years ago
Read 2 more answers
Which of the following contributes to the phases of the Moon as seen from Earth?
balandron [24]

Answer: Varying amounts of the Moon's lit surface being visible from Earth.

Explanation:

Phases of the moon can be defined as the different shapes of the moon visible from the Earth. This happens because sun lits up the face of moon and due to different position of moon in the orbit around earth, varying portion of the lit surface of the moon is visible from Earth. Refer to the diagram below:            

4 0
3 years ago
Read 2 more answers
HELP URGENT!!!!!!!!!!!!!!!!!!!!!!!!
nirvana33 [79]
D
Because the rest of the answers are illogical
5 0
3 years ago
A particle passes through the point P=(−3,1,0)P=(−3,1,0) at time t=3t=3, moving with constant velocity v⃗ =⟨5,3,−2⟩v→=⟨5,3,−2⟩.
eimsori [14]

Answer:

The parametric equation for the position of the particle is (-18+5t,-8+3t,6-2t).

Explanation:

Given that,

The point is

P=(-3,1,0)

Time t = 3

Velocity v=(5,3,-2)

We need to calculate the parametric equation for the position of the particle

Using parametric equation for position

r(t)=r_{0}+v(t)t....(I)

at t = 3,

P=r(t)

Put the value into the formula

(-3,1,0)=r_{0}+(5,3,-2)\times3

(-3,1,0)=r_{0}+(15,9,-6)

r_{0}=(-18,-8,6)

Put the value of r₀ in equation (I)

r(t)=(-18,-8,6)+(5,3,-2)t

r(t)=(-18+5t,-8+3t,6-2t)

Hence, The parametric equation for the position of the particle is (-18+5t,-8+3t,6-2t).

3 0
3 years ago
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