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kati45 [8]
3 years ago
15

What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

Chemistry
2 answers:
lutik1710 [3]3 years ago
8 0

Answer: 1.5 M

Explanation:

Fudgin [204]3 years ago
4 0
Molar mass NaOH = 39.997 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 30 / 39.997

n = 0.00075 moles of NaOH

Volume in liters:

500 mL / 1000 => 0.5 L

Therefore :

M = moles of solute / volume ( L )

M = 0.00075 / 0.5

M = 0.0015 mol/L
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The gain of electrons by an element or ion in a reaction is called __.
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Answer:

Reduction

Explanation:

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2 years ago
A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio
MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass  / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758  grams

Thus, the percent yield for this reaction = \frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100

or

the percent yield for this reaction = \frac{0.53}{0.5758}\times100

or

the percent yield for this reaction = 92.04%

6 0
3 years ago
Thermal energy is what we call energy that come from ___ of matter
kvv77 [185]

Answer:

Thermal energy is a kinetic form of energy that comes from the <u>temperature </u>of matter

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2 years ago
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3 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
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