Question

What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

Answer 1

Answer: 1.5 M

Explanation:

Answer 2

Molar mass NaOH = 39.997 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 30 / 39.997

n = 0.00075 moles of NaOH

Volume in liters:

500 mL / 1000 => 0.5 L

Therefore :

M = moles of solute / volume ( L )

M = 0.00075 / 0.5

M = 0.0015 mol/L