Y - 1 = 4y - 2/3. Move the ys over to one side, +4y crosses over to become -4y,
and -1 crosses over the right side to become +1.
y -4y = -2/3 + 1
-3y = 1 - 2/3
-3y = 1/3 Divide both sides by -3.
-3y/-3 = (1/3) / -3.
y = 1/3 * -1/3
y = - 1/9
We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer:
Following are the response to the given question:
Step-by-step explanation:
Move b a bit further if the angle between cd and ab changes when you move b if you want to make a perpendicular point to cd The angle BEC is 90 ° for making the AB line perpendicular to the line CD to transfer point B to the angle between the two lines.