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Effectus [21]
4 years ago
10

If a fast-moving car making a loud noise approaches and moves past the person, what will happen as the distance between the two

increases?
A. The pitch of the sound being heard by the person will appear to be higher than the pitch of the source.
B. The frequency of the sound waves reaching the person's ear will be greater than the frequency of the waves leaving the car.
C. The pitch of the sound being heard by the person will appear to be lower than the pitch of the source.
D. The pitch and frequency of the sound waves reaching the person's ear will remain unchanged.
Physics
2 answers:
densk [106]4 years ago
5 0
C.  The Pitch of the sound being heard by the person will appear to be lower than the pitch of the source.  I hope this is right

vladimir2022 [97]4 years ago
3 0
The answer is B.
The frequency will be greater


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you will be the trees
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8 0
2 years ago
All of the following are si base units except:_______
Shtirlitz [24]

Answer:

e. mole

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6 0
3 years ago
A motorist makes a trip 180 miles. For the first 90 miles she drives the remaining distance of her speed for the total trip is t
Minchanka [31]

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3 0
3 years ago
What units must the constant G have in order for the u it’s F to be newtons (N)?
EleoNora [17]

The units for G must be [N][m^2][kg^{-2}]

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

F is the force

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

We know that:

  • The units of F are Newtons (N)
  • The units of m_1,m_2 are kilograms (kg)
  • The units of r are metres (m)

So, we can rewrite the equation in terms of G, to find its units:

G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]

Learn more about gravitational force:

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5 0
3 years ago
Suppose a 65.5 kg gymnast climbs a rope. What is the tension in the rope if she climbs at a constant speed
natali 33 [55]

The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Given:

Mass of gymnast, m = 65.5 kg

The speed 'v' of gymnast is constant

Solution:

Consider the free-body diagram of the system as shown below.

Balancing forces along the vertical axis we get:

ΣFy = 0

Thus, we get:

F = ma     - (1)

where, m is mass of gymnast

            a is acceleration of gymnast (a = 0m/s², as the speed is constant)              

Also,

F = T - mg          -(2)

where, T is tension in the rope

           g is acceleration due to gravity

Equating (1) & (2), we get:

ma = T - mg

Re-arranging the equation, we get:

T = m(a+g)

Applying values in above equation we get:

T = (65.5 kg)(0 m/s²+9.8 m/s²)

T = 641.9 N

Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

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7 0
2 years ago
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