Answer: 1-82 2-7.4 3-355 4-.93
Explanation:
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Answer:
(a) HCl
(b) HCl
(c) HCl
(d) HCl
Explanation:
<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl
Using stoichiometry we can calculate the answers to parts a, b, c, and d.
<h3>Part (a) </h3>
# of moles × Avogadro's number = # of atoms or molecules
Avogadro's number: 6.02 * 10²³
HCl has more atoms than CH₄.
<h3>Part (b) </h3>
This is calculated the same way as Part (a); HCl has more molecules than CH₄.
<h3>Part (c) </h3>
Molar mass of CH₄ = 16.04 g/mol
Molar mass of HCl = 36.458 g/mol
HCl has a greater mass than CH₄.
<h3>Part (d)</h3>
Assuming STP:
Molar volume of any gas at STP is 22.4 L/mol.
HCl has a greater volume than CH₄.
The answer is -0.22 for the total impact of velocity 1.1 seconds -5.0=-
B. Suspensions is the answer
The answer is; C
These lines that join areas of equal pressure during an air system are called isobars. The black lines in the diagram below are the isobars. They are good indicators of the strength of these systems. The innermost closed lines indicate the positions of relative maxima (high-pressure areas) and minima (low-pressure areas) in the pressure field.