3 years ago

Please answer offering a lot of points and give brainliest pleaseeeee

Physics

1 answer:

asambeis [7]3 years ago

3 0

23 is the right answer.

You might be interested in

Which process is used to make a semiconductor into a transistor?

Klio2033 [76]

Answer:

Explanation:

Adding a dopant is correct on edge.

6 0

3 years ago

Read 2 more answers

Draw vectors to represent these motions:<br>moving 3 cm to the right<br>moving 2 cm to the left

Ira Lisetskai [31]

Vector. Oh yeeeeeeeeahhh

7 0

2 years ago

Two forces act on an object. The first force has a magnitude of 15.0 N and is oriented 78.0 ° counterclockwise from the + x ‑axi

bezimeni [28]

Answer:

Explanation:

fffkfkfk

4 0

3 years ago

If you know this please help me !!

Alecsey [184]

When atoms lose electrons they become positively charged ! When atoms gain electrons they become negatively charged !

5 0

3 years ago

The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9

Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

$P=\frac{90I}{I^2+I+9}$

now differentiating the above equation with respect to Intensity 'I' we get

$\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}$

$\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}$

Now for the maxima $\frac{dP}{dI}=0$

thus,

$0=\frac{-90I^2+810)}{(I^2+I+9)^2}$

$-90I^2+810=0$

$I^2=\frac{810}{90}$

$I^2=9$

I = 3

thus, <u>for the value of intensity I = 3, the P is maximum</u>

at I = 3

$P=\frac{90\times3}{3^2+3+9}$

$P=\frac{270}{21}$

$P=12.85$

5 0

3 years ago