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Hunter-Best [27]
3 years ago
12

A 0.25 kg harmonic oscillator has a total mechanical energy of 4.1 j. if the oscillation amplitude is 20.0 cm, what is the oscil

lation frequency?
Physics
2 answers:
laiz [17]3 years ago
7 0
When the oscillator is at maximum extension, we know all of its energy is in Potential Energy, so if the total oscillation energy is 4.1 J, we know that at maximum displacement of 0.2 m, that 

<span>energy = 1/2 kA^2 where A= 0.2 m </span>

<span>k= 2E  / A^2 = 2*4.1 J /0.2^2=200 N/m </span>

<span>the frequency of oscillation is (1/2pi) sqrt[k/m] </span>

<span>knowing k and m, we can substitute values and find frequency</span>
blondinia [14]3 years ago
6 0

Answer:

4.6Hz

Explanation:

We first have to derive Oscillation Frequency formula

Maximum velocity = Vmax = wA

Energy = 1/2m(Vmax)²

Energy = 1/2m(wA)²

Frequency = w/2π

Hence,

Oscillation Frequency Formula is given as

F =( 1/2πA)× √2E/m

where in the question,

A = Amplitude = 20.0cm

We convert 20.0cm to meter

100cm = 1m

20cm = ?

= 20÷100 = 0.20m

E = Mechanical energy = 4.1j

m = mass = 0.25kg

Frequency =( 1/2π × 0.20m) × √(2×4.1j)/0.25kg

Frequency = 4.558Hz

Oscillatory frequency approximately is = 4.6Hz

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How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
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Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

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W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

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