As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?
Answer:
v = 21 m / s
Explanation:
We can solve this exercise with the kinematics equations, let's start by finding the acceleration of the train with the initial data
v = v₀ + a t
the initial speed is the speed within the city 6 m / s, the final speed is v = 11 m / s and the time is t = 8 s
a = (v-v₀) / t
a = (11 - 6) / 8
a = 0.625 m / s²
when it leaves the city with speed vo = 11 m / s it accelerates for t = 16 s
v = v₀ + a t
v = 11 + 0.625 16
v = 21 m / s
<em>Answer: D</em>
<em>Given data:</em>
The electric field due to charge q₁ is (E₁) = 1.5 × 10⁵ N/C
The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C
Determine the net electric field at point P (Enet) = ?
electric field measured in Newtons/coulomb
<em>We know that,</em>
The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively
Enet = E₁ + E₂
= (1.5 × 10⁵)+ (7.2 × 10⁵)
= 8.7 × 10⁵ Newtons/coulomb
<em>The net electric field at point P is 8.7 × 10⁵ N/C</em>
Answer:
the answer would be "using more heat" btw
Explanation:
B. Unless you add more water molecules or you add a new substance, the mass should stay the same no matter what.
