3 years ago

What change of state occurs during vaporization? liquid to gas gas to liquid solid to liquid liquid to solid

Physics

2 answers:

nignag [31]3 years ago

8 0

Answer:

A is correct!

Explanation:

e2020

defon3 years ago

7 0

Answer:

Explanation:

right on edge :)

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A _ system is one in which one subsystem provides services to another subsystem.

astra-53 [7]

Answer:

Explanation:

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3 years ago

Read 2 more answers

In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-l

NNADVOKAT [17]

Answer:

The diver is in the air for $1.65s$ .

Explanation:

Known data $v_{i}=6.3m/s, y_{i}=3.0m$ and $g=9.8m/s^{2}$ .

We need to find the time when the diver reaches the highest point, so we use the following equation $v_{f} =v_{i}-gt$ with $v_{f}=0ms$ so $t_{1}=\frac{v_{i}-v_{f} }{g}=\frac{6.3m/s}{9.8m/s^{2} }=0.64 s$ .
Then we need to find the highest point, so we use $y=v_{i}t-\frac{1}{2} gt^{2}=(6.3m/s)(0.64s)-\frac{1}{2} (9.8m/s^{2})(0.64s)^{2}=2.03m$ , this is above the springboard so the highest point is $y_{max}=5.03m$ .

Finally, we need to find the time in free fall, so we use $y_{f}=y_{i}+v_{i}t-\frac{1}{2}gt^{2}$ , at this stage $v_{i}=0m/s, y_{i}=5.03m$ and $y_{f}=0m$ , therefore we have $0m=5.03-\frac{1}{2}(9.8m/s^{2})t^{2}$ , and solving for $t_{2}=\sqrt{\frac{5.03m}{4.9m/s^{2}}} =\sqrt{1.02s^{2}}=1.01s$ .