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3 years ago

What change of state occurs during vaporization? liquid to gas gas to liquid solid to liquid liquid to solid

Physics

2 answers:

nignag [31]3 years ago

8 0

Answer:

A is correct!

Explanation:

e2020

defon3 years ago

7 0

Answer:

Explanation:

right on edge :)

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A basketball player makes a jump shot. The 0.599 kg ball is released at a height of 2.18 m above the floor with a speed of 7.05

7nadin3 [17]

Answer:

$W_{drag} = 4.223\,J$

Explanation:

The situation can be described by the Principle of Energy Conservation and the Work-Energy Theorem:

$U_{g,A}+K_{A} = U_{g,B} + K_{B} + W_{drag}$

The work done on the ball due to drag is:

$W_{drag} = (U_{g,A}-U_{g,B})+(K_{A}-K_{B})$

$W_{drag} = m\cdot g\cdot (h_{A}-h_{B})+ \frac{1}{2}\cdot m \cdot (v_{A}^{2}-v_{B}^{2})$

$W_{drag} = (0.599\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.18\,m-3.10\,m)+\frac{1}{2}\cdot (0.599\,kg)\cdot [(7.05\,\frac{m}{s} )^{2}-(4.19\,\frac{m}{s} )^{2}]$

$W_{drag} = 4.223\,J$

7 0

3 years ago

Read 2 more answers

The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?

kipiarov [429]

magnification = $\bf\dfrac{height of image}{height of object}$

= $\bf\dfrac{6cm}{10cm}$

= 0.6

3 0

2 years ago

A truck of mass 500kg moving at 4m/s collides with another truck of mass 1500kg moving in the same direction at 2m/s. What is th

VMariaS [17]

Answer:

m1u1+m2u2=(m1+m2)v.

500×4+1500×2=(500+1500)V.

2000+3000=2000V.

5000=2000V.

V=2.5m/s

8 0

3 years ago

What is the velocity of a quarter dropped from a tower after 10 seconds?

Goryan [66]

U = 0, the initial vertical velocity

Assume g = 9.8 m/s² and ignore air resistance.

Use the formula
v = u + gt
where v = vertical velocity after t seconds.
That is,
v = 0 + (9.8 m/s²)*(10 s) = 98.0 m/s

Answer: 98.0 m/s

3 0

3 years ago

A very long stick ruled with meter markings is placed in empty space. A spaceship of rest length L = 100 m runs lengthwise along

alexira [117]

Answer:

Meter marks are on cut-off portion of stick is 100 - 60 = 40 m

Explanation:

Given data:

Spaceship length of L = 100 m

Relative velocity between the ship and stick is given as

$v = \frac{4}{5} c$