Answer:

Explanation:
The situation can be described by the Principle of Energy Conservation and the Work-Energy Theorem:

The work done on the ball due to drag is:


![W_{drag} = (0.599\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.18\,m-3.10\,m)+\frac{1}{2}\cdot (0.599\,kg)\cdot [(7.05\,\frac{m}{s} )^{2}-(4.19\,\frac{m}{s} )^{2}]](https://tex.z-dn.net/?f=W_%7Bdrag%7D%20%3D%20%280.599%5C%2Ckg%29%5Ccdot%20%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%5Ccdot%20%282.18%5C%2Cm-3.10%5C%2Cm%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%280.599%5C%2Ckg%29%5Ccdot%20%5B%287.05%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D-%284.19%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D)

Answer:
m1u1+m2u2=(m1+m2)v.
500×4+1500×2=(500+1500)V.
2000+3000=2000V.
5000=2000V.
V=2.5m/s
U = 0, the initial vertical velocity
Assume g = 9.8 m/s² and ignore air resistance.
Use the formula
v = u + gt
where v = vertical velocity after t seconds.
That is,
v = 0 + (9.8 m/s²)*(10 s) = 98.0 m/s
Answer: 98.0 m/s
Answer:
Meter marks are on cut-off portion of stick is 100 - 60 = 40 m
Explanation:
Given data:
Spaceship length of L = 100 m
Relative velocity between the ship and stick is given as

The observed length observed by the outside observer is

putting all value to get observe length
put

L' = 60 m
Meter marks are on cut-off portion of stick is 100 - 60 = 40 m