<span>When the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be going up until all the forces of gravity would dominate and change the direction of the rocket. We need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.
Given:
a = 86 m/s^2
t = 1.7 s
Solution:
d = vi (t) + 0.5 (a) (t^2)
d = (0) (1.7) + 0.5 (86) (1.7)^2
d = 124.27 m
vf = vi + at
vf = 0 + 86 (1.7)
vf = 146.2 m/s (velocity when the fuel is consumed completely)
Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at
0 = 146.2 + (-9.8) (t)
t = 14.92 s
Then, the second distance
d= vi (t) + 0.5 (a) (t^2)
d = 146.2 (14.92) + 0.5 (-9.8) (14.92^2)
d = 1090.53 m
Then, we determine the maximum altitude:
d1 + d2 = 124.27 m + 1090.53 m = 1214.8 m</span>
Answer:
Random Motion is a motion in which an object didn't go in a straight manner, for ex: zig zag lines, curved, etc.
Explanation:
To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.
From the definition we know that the speed of a body can be described as a function of gravity and height
Then applying the kinematic equation of displacement, the height can be written as
Re-arrange to find t,
Thus the calculation of the displacement would be subject to
Therefore the required distance must be 0.547m
Oceans and Lakes are part of the Hydrosphere.
The ball's horizontal position 
and vertical position 
at time 
are given by
where 
, 
, and 
. The ball reaches the ground when 
at
(we don't care about 
)
At this time, the ball's horizontal position is
which you might recognize as the range formula. With the known parameters, the ball thus traverses a range of
