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sashaice [31]
4 years ago
5

Use p = (m*v)/sqrt( 1 − v^2/c^2) and E = (m*c^2)/sqrt( 1 − v^2/c^2) to derive

Physics
1 answer:
bogdanovich [222]4 years ago
3 0

Answer:

idk sorry

Explanation:

this looks confusing to me

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Which type of evidence was used to tie Ted Bundy to the murder of Lisa Levy?
Elodia [21]

Explanation:

identified by one of the Chi Omega survivors as the assailant, and hair and fiber evidence tied him to the Leach murder. His trial for the Florida attacks in June 1979 was the first-ever nationally televised trial in the United States.

6 0
2 years ago
A ball which is dropped from the top of a building strikes the ground with a speed of 30m/s. Assume air resistance can be ignore
Vika [28.1K]

Answer:

               h= 45.87 m.

Explanation:

Data given:

Vf= 30m/s ,     and we know that g = 9.8 m/s²    

The ball has an initial velocity of zero      Vi = 0 m/s²    

To Find:

Height of the building = ?

Solution:

       According to 3rd law of the motion;

                                      2aS= Vf² - Vi²                      ( S= h , a=g)

                                     2*9.81*h = (30)² - (0)²

                                      h= 45.87 m.

3 0
3 years ago
A spring that is stretched by hanging a 5kg mass. It's equilibrium length was 0.5 meters. Now the length of the spring is 1.6 me
gtnhenbr [62]
45 N/m as attached, please comment

5 0
3 years ago
A downhill skier was able to move 560 meters in 25 seconds. What is the skier’s average speed? (Round your answer to the nearest
slava [35]
Speed is distance in a specific time period. When someone ask use the unit "m/s" this period of time is one second. If the skier was able to move 560 m in 25 seconds, in one second how much distance he moves? That is the question.
You can solve this problem like
560m/25s = 22,4 m/s
Good luck!

6 0
3 years ago
Read 2 more answers
In a jump spike, a volleyball player slams the ball from overhead and toward the opposite floor.
USPshnik [31]
V ( initial ) = 20 m/s
h = 2.30 m
h = v y * t + g t ² / 2
d = v x * t
1 ) At α = 18°:
v y = 20 * sin 18° = 6.18 m/s
v x = 20 * cos 18° = 19.02 m/ s
2.30 = 6.18 t + 4.9 t²
4.9 t² + 6.18 t - 2.30 = 0
After solving the quadratic equation ( a = 4.9, b = 6.18, c = - 2.3 ):
t 1/2 = (- 6.18 +/- √( 6.18² - 4 * 4.9 * (-2.3)) ) / ( 2 * 4.9 )  
t = 0.3 s
d 1 = 19.02 m/s * 0.3 s = 5.706 m
2 ) At  α = 8°:
v y = 20* sin 8° = 2.78 m/s
v x = 20* cos 8° = 19.81 m/s
2.3 = 2.78 t + 4.9 t² 
4.9 t² + 2.78 t - 2.3 = 0
t = 0.46 s
d 2 = 19.81 * 0.46 = 9.113 m
The distance is:
d 2 - d 1 = 9.113 m - 5.706 m = 3.407 m
7 0
3 years ago
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