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Darina [25.2K]
3 years ago
7

What is the first step in a mass- mole or mass to mass problem?

Chemistry
1 answer:
Sedaia [141]3 years ago
4 0
Mass to mass: moles A x(mole ratio of B/A) and mass to mole: extract the data from the question
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Answer:

nitrogen is the answer because of the same position of group in periodic table

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What is the significance of the symbol and formula​
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Explanation:

Importance of symbols and Formulae :

Symbols and formulae of substance gives a lot of information like. Types of elements present in the compound. E.g. (H20 is made of two elements hydrogen and oxygen). Number of each kind of atoms in one molecule.

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PH que tendra una solución cuya concentracion de [OH-] = 1x10-4
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3 years ago
The difference between ATP and the nucleoside triphosphates used during DNA synthesis is that:
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Answer:

The correct answer is <em>d. The nucleoside triphosphates have the sugar deoxyribose; ATP has the sugar ribose.</em>

Explanation:

The nucleoside triphosphates are components of DNA (deoxyribonucleic acid) so they are composed by a nitrogenous base (adenine, guanine, thymine or cytosine) and a deoxyribose sugar. In contraposition, ATP (adenosine triphosphate) is composed by the nitrogenous base adenine and a ribose sugar along with three phosphates groups. Unlike ribose, deoxyribose is a 5-carbon sugar which lack of an oxygen atom in C2 position.

4 0
3 years ago
How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0
3 years ago
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