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Marina86 [1]
3 years ago
5

1. How many atoms are in 0.25 moles of carbon?

Chemistry
1 answer:
erastovalidia [21]3 years ago
7 0

Answer    1 mole = 6.02 × 1023 atoms

0.25 moles × (6.02 × 1023) = 1.5 × 1023 atoms Carbon

for the first one

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What is the conversion of 12.044x10^23 to a gram
postnew [5]

Answer:

8.4g

Explanation:

6 0
3 years ago
11. How did the solubility product constant Ksp of KHT in pure water compare to its solubility product constant Ksp of KHT in KC
Airida [17]

Answer:

Explanation:

KHT is a salt which ionises in water as follows

KHT ⇄ K⁺ + HT⁻

Solubility product Kw= [ K⁺ ] [ HT⁻ ]

product of concentration of K⁺ and HT⁻ in water

In KCl solution , the solubility product of KHT will be decreased .

In KCl solution , there is already presence of K⁺  ion in the solution . So

in the equation  

[ K⁺ ] [ HT⁻ ]  = constant

when K⁺ increases [ HT⁻ ] decreases . Hence less of KHT dissociates due to which its  solubility decreases . It is called common ion effect . It is so because here the presence of common ion that is K⁺ in both salt to be dissolved and in solvent , results in decrease of solubility of the salt .

7 0
3 years ago
Classify each of these reactions. Ba ( ClO 3 ) 2 ( s ) ⟶ BaCl 2 ( s ) + 3 O 2 ( g ) acid–base neutralization precipitation redox
Blababa [14]

Answer:

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂(aq) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

Explanation:

Redox reaction involves the oxidation states. The oxidation state from an element decreases and the oxidation state from other element increases.

It is called redox because one element reduces and the other oxidizes.

Neutralization reaction occurs when an acid and a base react, to produce water an a determined salt.

Precipitation reaction can be produced when a solid is formed as the reactants react.

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

Cl changes the oxidation state from 5 to -1  (reduction)

O changes the oxidation state from -2 to 0 (oxidation)

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂( aq ) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

3 0
3 years ago
During beta-oxidation of fatty acids, ___________ is produced in peroxisomes but not in mitochondria. A) acetyl-CoA B) FADH 2 C)
stepan [7]

Answer:

The correct option is D

Explanation:

Normally, beta-oxidation of fatty acid occurs in the mitchondrial matrix, however, when the fatty acid chains are too long, the beta-oxidation occurs in the peroxisomes <u>where the oxidation is not attached to ATP synthesis but rather transferred (i.e high energy electrons are transferred) to O₂ to form hydrogen peroxide</u> (H₂O₂). This is the major difference between the beta-oxidation that occurs in the peroxisomes to that which occurs in the mitochondria.

4 0
3 years ago
Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,l,ml,ms).a. 3,1,1,-1/2b. 4,3,1,-1/2c. 2
Vladimir79 [104]

Answer:

The valid set of quantum numbers are:

a. 3,1,1,-1/2

b. 4,3,1,-1/2

c. 2,0,0,-1/2

e. 3,2,-1,-1/2

j. 3,0,0,1/2

Explanation:

Quantum numbers (n, l, mℓ, ms) are the set of numbers that describe the state of an electron in an atom.

<u>The four quantum numbers and their rules are</u>:

  1. Principal: n ≥ 1  
  2. Azimuthal: ℓ ≤ (n-1)
  3. Magnetic: mℓ = (- ℓ) to (+ ℓ)
  4. Spin: ms = (- s), (+ s)  

Therefore,

a. 3,1,1,-1/2: <em>Valid</em>

b. 4,3,1,-1/2: <em>Valid</em>

c. 2,0,0,-1/2: <em>Valid</em>

d. 1,3,0,1/2: <u>NOT</u> <em>Valid</em>

<u>Reason</u>: ℓ ≤ (n-1). Therefore, ℓ can not be greater than n, .

e. 3,2,-1,-1/2: <em>Valid</em>

f. 3,3,-1,1/2: <u>NOT</u><em> Valid</em>

<u>Reason:</u> ℓ ≤ (n-1). Therefore, ℓ can not be equal to n. (ℓ ≠n)

g. 3,2,1,-1: <u>NOT</u> <em>Valid</em>

Reason: the only allowed values of ms = (- s), (+ s) = (- 1/2), (+ 1/2)

h. 1,-1,-1,-1/2: <u>NOT </u><em>Valid</em>

<u>Reason</u>: ℓ ≤ (n-1) and n ≥ 1. Therefore, ℓ can not be equal to n and also ℓ can't be negative.

i. 3,3,1,1/2: <u>NOT </u><em>Valid</em>

<u>Reason:</u> ℓ ≤ (n-1). Therefore, ℓ can not be equal to n. (ℓ ≠n)

j. 3,0,0,1/2: <em>Valid</em>

k. 4,3,4,-1/2: <u>NOT </u><em>Valid</em>

<u>Reason</u>: mℓ = (- ℓ) to (+ ℓ). Therefore, mℓ can't be greater than ℓ.

l. 0,2,1,1/2: <u>NOT </u><em>Valid</em>

<u>Reason:</u> n ≥ 1. Therefore, value of n can't be 0 (n≠0)

4 0
3 years ago
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