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Novay_Z [31]
3 years ago
11

Electrical charges were named by? Franklin, Gilbert , van de graaff

Physics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

franklin im pretty sure??

Explanation:

, Electrical engineering from Dr. B. C. Roy Engineering College, Durgapur (2019) In the 18th century, Benjamin Franklin in America tried experiments with charges. It was Franklin who named the two kinds of electricity

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A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension
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To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

F_c = \frac{mv^2}{r}

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

m = 0.4kg\\r = 0.75m\\F_c = 450N

Rearranging to find the velocity we have that,

F_c = \frac{mv^2}{r}

v = \sqrt{\frac{F_c * r}{m}}

v = \sqrt{\frac{450 * 0.75}{0.4}}

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The average energy of the atoms that make up a substance which is changing from a liquid to a solid is
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A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the
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Answer:

a    D = 3.9 *10^{-12} \ m

b    \tau_{max} = 1.24 *10^{-25} \  N\cdot m

c   W =  2.48 *10^{-25} J

 

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \sigma  =  6.2 *10^{-30} \ C \cdot m

     The electric field is E =  2*10^{4} \ N/C

   

The distance between the positive and negative charge center is mathematically evaluated as

     D =  \frac{\sigma }{10 e}

Where  e is the charge on one electron which has a constant value of  e = 1.60 *10^{-19} \ C

  Substituting values

     D =  \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}

      D = 3.9 *10^{-12} \ m

The maximum torque is mathematically represented as

       \tau_{max} = \sigma * E  * sin (\theta)

Here  \theta  =  90^o

This because at maximum the molecule is perpendicular to the field

    substituting values

       \tau_{max} =  6.2 *10^{-30} * 2*10^{4} sin ( 90)

       \tau_{max} = 1.24 *10^{-25} \  N\cdot m

The workdone is mathematically represented as

      W =  V_{(180)} - V_{0}

where   V_{(180)} is the potential energy at 180° which is mathematically evaluated as

     V_{(180) } = -   \sigma  * E  cos (180)

Where the negative signifies that it is acting against the  field

   substituting values

     V_{(180) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (180)

      V_{(180) } = 1.24*10^{-25} J

and

     V_{(0)} is the potential energy at 0° which is mathematically evaluated as

            V_{(0) } = -   \sigma  * E  cos (0)

   substituting values

     V_{(0) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (0)

      V_{(0) } =- 1.24*10^{-25} J

So W =  1.24 *10^{-25} - [-1.24 *10^{-25}]

    W =  2.48 *10^{-25} J

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4 years ago
How does a bicycles kinetic energy change when it slows down?
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