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DerKrebs [107]
3 years ago
14

The power in an electric circuit varies inversely with the resistance. If the power is 2,200watts when the resistance is 25 ohms

, find the resistance when the power is 1,100watts.
Physics
2 answers:
lana66690 [7]3 years ago
8 0

Answer:

50ohms

Explanation:

If the power in an electric circuit varies inversely with the resistance, it can expressed as P = k/R where;

P is the power, R is the resistance and k is the constant of proportionality.

From the formula, k = PR

k = P1R1 = P2R2...(1)

Given P1 = 2200watts, R1 = 25ohms, P2 = 1100watts R2 = ?

From equation (1);

R2 = P1R1/P2

R2 = 2200×25/1100

R2 = 50ohms

The resistance when the power is 1100watts is 50ohms.

This shows that as the power is decreasing, the resistance is increasing.

user100 [1]3 years ago
4 0

Answer:

50 ohms

Explanation:

From Electricity,

P ∝ 1/R

PR = k

P'R' = PR................. Equation 1

Where P' = Initial power, R' = Initial resistance, P = Final power, R = Final resistance

Make R the subject of the equation

R = P'R'/P.................... Equation 2

Given: P' = 2200 watts, P = 1100 watts, R' = 25 ohms

Substitute into equation 2

R = 2200(25)/1100

R = 50 ohms

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Answer:

charge C = greatest net force

charge B = the smallest net force

ratio  = 9 : 1

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F(c) = F2 + F 1 + F 1      ....................4

F(c) = \frac{k\ q^2}{4d^2}+\frac{k\ q^2}{d^2}+\frac{k\ q^2}{d^2}      

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