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fredd [130]
3 years ago
15

Which example best demonstrates how unbalanced forces change the speed of an object's motion? A) A child on a bicycle braking at

a stop sign. B) A child singing a song. C) A child sitting in a chair reading a book. Eliminate D) A child walking around the corner of a school hallway.
Physics
2 answers:
sleet_krkn [62]3 years ago
6 0

Answer:

The correct answer is A.

Explanation:

Unbalanced forces change the speed of movement of an object because they act non-uniformly on the object to which they relate. When a child on a bicycle brakes on a stop sign, the brakes act unevenly on the wheel, causing an uneven decrease in speed. In this way, you lose the balance of the movement you had prior to braking.

Have a nice day!

SCORPION-xisa [38]3 years ago
5 0
The answer would be A :)
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A resonant circuit using a 286-nFnF capacitor is to resonate at 18.0 kHzkHz. The air-core inductor is to be a solenoid with clos
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Answer:

The inductor contains N = 523962.32 loops  

Explanation:

From the question we are told that

     The capacitance of the capacitor is  C =  286nF = 286 * 10^{-9} \  F

      The resonance frequency is  f = 18.0 kHz =  18*10^{3} Hz

       The diameter is  d =  1.1 mm = \frac{1.1 }{1000} = 0.00011 \ m

       The  of the air-core inductor is l = 12 \ m

        The permeability of free space is  \mu_o = 4 \pi *10^{-7} \ T \cdot m/A

 

Generally the inductance of this air-core inductor is mathematically represented as

              L =  \frac{\mu_o * N^2 \pi d^2}{4 l}

This inductance can also be mathematically represented as

               L = \frac{1}{w^2}

Where w is the angular speed mathematically given as

             w = 2 \pi f

So

            L =  \frac{1}{4 \pi ^2 f^2}

Now equating the both formulas for inductance

         \frac{\mu_o * N^2 \pi d^2}{4 l}  =  \frac{1}{4 \pi ^2 f^2}

making N the subject of  the formula

              N = \sqrt{\frac{1}{(2 \pi f)^2} * \frac{4 * l }{\mu_o * \pi d^2 C}  }

              N =  \frac{1}{2 \pi f} * \frac{2}{d} * \sqrt{\frac{l}{\pi * \mu_o * C} }

             

 Substituting value

            N =  \frac{1}{ 3.142  * 18*10^{3} * 0.00011 }  \sqrt{\frac{12}{ 3.142  * 4 \pi *10^{-7}* 286 *10^{-9}} }

              N = 523962.32 loops  

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