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photoshop1234 [79]
2 years ago
8

The main light gathering device of a refractor telescope is

Physics
1 answer:
Nataly [62]2 years ago
3 0

It's the "objective" lens ... the big one in the front.

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ANTONII [103]
Acceleration = vf-vi /t
10-22/3=2.6m/s^2

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3 years ago
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The resistance of a very fine aluminum wire with a 20 μm × 20 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by w
notsponge [240]

Explanation:

The given data is as follows.

         Resistance (R) = 1200 ohm,     Area (A) = 20 \times 10^{-6} m (as 1 \mu m = 10^{-6} m)

            Diameter (d) = 2.3 mm = 2.3 \times 10^{-3} m

First, we will calculate the length as follows.

            R = \rho \frac{L}{A}

Here,  \rho = resistivity of aluminium = 2.65 \times 10^{-8}

Putting the given values above and we will calculate the value of length as follows.

               R = \rho \frac{L}{A}

             1200 = 2.65 \times 10^{-8} \times \frac{L}{20 \times 10^{-6}}

               L = 9.056 \times 10^{5}

As the circumference of circular wire = 2 \pi r

or,                                                          = 2 \times \pi \times \frac{d}{2}  

                                                              = \pi \times d

And, number of turns will be calculated as follows.

             No. of turns × Circumference = Length of wire

              No. of turns × 3.14 \times 2.3 \times 10^{-3} = 9.056 \times 10^{5}

                               = 1.25 \times 10^{8}

Thus, we can conclude that 1.25 \times 10^{8}  turns of wire are needed.

6 0
2 years ago
When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal
Temka [501]

Ans the answer is 0.25J

Explanation

i guess

4 0
3 years ago
A pendulum has a mass of 3kg and is lifted to a height of .3m. What is the maximum speed of the pendulum
Kryger [21]

Given data

*The given mass of the pendulum is m = 3 kg

*The given height is h = 0.3 m

The formula for the maximum speed of the pendulum is given as

v_{\max }=\sqrt[]{2gh}

*Here g is the acceleration due to the gravity

Substitute the values in the above expression as

\begin{gathered} v_{\max }=\sqrt[]{2\times9.8\times0.3} \\ =2.42\text{ m/s} \end{gathered}

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1 year ago
What is the weight of a bag that has the mass of 18.0kg
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39.6832 pounds would be your answer

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