Answer:
Explanation:
As we know that current density is ratio of current and area of the crossection
now we have
so the current through the wire is given as
now we have
here we have
now plug in the values in above equation
now we have
now plug in both limits as mentioned
here R = 2.11 mm
50 μm = 5 × 10⁻⁵ m in diameter
<h3>Steps</h3>
1μm = 1 x m
<h3>Given</h3>
1μm = 1 x m
50μm = 50 x m
50μm = 50 x 10 x
50μm = 5 x m
<h3>Conclusion</h3>
A human hair is approximately 50 μm = 5 × 10⁻⁵ m in diameter
<h3>How big is a human hair on average?</h3>
between 17 and 181 micrometers
The typical diameter of human hair can range from 17 micrometers to 181 micrometers, according to research. Using 50 micrometers as an average figure for its diameter, this translates to 50,000 nanometers.
<h3>What is a human hair's diameter in inches?</h3>
The finest hair is flaxen, with a diameter ranging from 1/1500 to 1/500 of an inch. the coarsest hair is black, measuring between 1/450 and 1/140 of an inch.
learn more about human hair diameter here
<u>brainly.com/question/13147893</u>
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Answer:
42
Explanation:
27.9+13+1.21=42.11
to a significant figure= 42
I am pretty sure that<span> the following which describes resistance force is the fourth option from the scale represented above : </span>D .force applied by the machine to overcome resistance. I choose this due to the Newton's 3rd law, as the<span> force that shoul be overcome by a machine before it perform its usual work. Do hope you will find it helpful! Regards!</span>
Answer:
N1 / N2 = 1.0016
Explanation:
The apparent weight of the student is the value that a balance would have this corresponds in this case to the normal of the student. Let's write Newton's second law in the lower and upper part of the loop
For lower rotating wheel
N1 - W = m a
a = v² / r
N1 = W + v² / r
The relationship between linear and angular velocity is
v = w r
As the wheel rotates at a constant speed, we can use angular kinematics
w = θ / t
θ = 3 rev (2π rad / 1rev) = 6π rad
w = 6π / 150
w = 0.04π rad / s = 0.1257 rad / sec
calculate
N1 = mg + w² r
N1 = 55 9.8 + 0.1257² 27
N1 = 539 + 0.4267
N1 = 539.426 N
Now we perform the same calculation for the top
-N2 - W = -m a
N2 = -W + ma
N2 = 539 - 0.4267
N2 = 538.5733 N
The relationship between the weight at the bottom and top is
N1 / N2 = 539.4267 / 538.5733
N1 / N2 = 1.0016