Answer:
206480
Step-by-step explanation:
Don't even bother with this part ever.
Answer:
If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams
Step-by-step explanation:
Mean = 
Standard deviation =
We are supposed to find If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than how many grams i.e.P(X>x)=0.02
The mean weight is in the highest 2%, you want to go to a z-table and find the z-score that where the area to the left of the curve is closest to 0.98.
n = 27
Refer the z -table
P(Z>x)=2.06

So, If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams
1.50 + 0.50x < 25 ; x < 47 miles 3rd option in the choices.
Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time
Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;
50%*15% = 0.5 * 0.15 = 7.5%
Therefore, the probability of missing both two-point conversion attempts is 7.5%
Answer:
$270
Step-by-step explanation: