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BaLLatris [955]
3 years ago
9

2. Michelle bought 15.6 yards of fabric. She used 5.43 yards in her art 10 points

Physics
1 answer:
viktelen [127]3 years ago
8 0
Do find the percentage you:
5.43/15.6=0.34

Time by 100:
34%

Closest answer is 35%

Hope this helps ;)
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An overhead electric power line carries a maximum current of 125 A. What is the magnitude of the maximum magnetic field at a poi
BARSIC [14]

Answer:

B= 55.6×10^(-7) Tesla

Explanation:

B= μoI/(2πr)

B:  magnetic field strength

μo: permeability of free space and is equal to  4π×10^(-7) T.m/A

r: distance from the wire

I : current in the wire

B= (4π×10^(-7)×125)/(2π×4.5)

B= 55.6×10^(-7) Tesla

3 0
3 years ago
Find the energy in Joules required to lift a 55.0 Megagram object a distance of 500 cm.
fredd [130]

Energy to lift something =

               (mass of the object) x (gravity) x (height of the lift).

BUT ...

This simple formula only works if you use the right units.

Mass . . . kilograms
Gravity . . . meters/second²
Height . . . meters

For this question . . .

Mass = 55 megagram = 5.5 x 10⁷ grams = 5.5 x 10⁴ kilograms

Gravity (on Earth) = 9.8 m/second²

Height = 500 cm  =  5.0 meters

So we have ...

Energy = (5.5 x 10⁴ kilogram) x (9.8 m/s²) x (5 m)

            =  2,696,925 joules .

That's quite a large amount of energy ... equivalent to
straining at the rate of 1 horsepower for almost exactly an
hour, or burning a 100 watt light bulb for about 7-1/2 hours.

The reason is the large mass that's being lifted.
On Earth, that much mass weighs about 61 tons.

7 0
2 years ago
Describe a situation when you might travel at a high velocity, but with low acceleration
Alisiya [41]

Reading a book in your warm, comfy seat ... in Row-27 of a
passenger airliner cruising at 450 miles per hour.
 
5 0
3 years ago
Why does straightening the curve not change the equation that represents the graph
Sphinxa [80]
<span>You cant change the curve of a graph with out changing the equation</span>
3 0
3 years ago
Read 2 more answers
A truck is traveling on a level road. The driver suddenly applies the brakes, causing the truck to decelerate by an amount g/2.
adoni [48]

Answer:

Truck \dfrac{g}{10}

Road -\dfrac{g}{10}

Explanation:

a_1 = Acceleration of truck = -\dfrac{g}{2}

\mu = Coefficient of friction = \dfrac{2}{5}

Frictional force is given by

f=-\mu mg\\\Rightarrow f=-\dfrac{2}{5}mg\\\Rightarrow ma_2=-\dfrac{2}{5}mg\\\Rightarrow a_2=-\dfrac{2}{5}g

Net acceleration is given by

a=a_2-a_1\\\Rightarrow a=-\dfrac{2}{5}g+\dfrac{g}{2}\\\Rightarrow a=\dfrac{g}{10}

The acceleration of the box relative to the truck is \dfrac{g}{10} and -\dfrac{g}{10} relative to the road.

4 0
2 years ago
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