1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Orlov [11]
4 years ago
8

What sort of waves exhibit the doppler effect?

Physics
1 answer:
Alexus [3.1K]4 years ago
7 0
The waves that occur when you drop and stone into the water when skipping rocks
You might be interested in
How should i fix an overfilled ballon? its my sisters 3rd birthday and i have overfilled all the ballons and there is no other o
iVinArrow [24]
Try to untie the knot and let a little air out and tie it back.....
8 0
3 years ago
A voltage amplifier needs a high input resistance and a low output resistance. Select one: True False
cupoosta [38]

Answer:

Explanation:

In electric circuit , the potential difference is always developed across the resistance .

Now is we are to amplify the voltage , that means low input voltage is converted into high voltage output .

Therefore we require low resistance at input for low voltage and high out put resistance for high output

Thus the statement given is wrong .

6 0
3 years ago
The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

Answer:

e=3367.2J

%e=1.43%

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

v_{r}=10km/h=2.77m/s

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s

Knowing that we can calculate Kinetic energy for the real and experimental speed

E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J

E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

%e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43%

4 0
4 years ago
1) What kind of energy is gained when your roller coaster goes uphill?
Dvinal [7]

1) Gravitational potential energy

In fact, gravitational potential energy is given by: GPE=mgh

where m is the mass of the roller coaster, g is the gravitational acceleration and h is the heigth. Therefore, when the roller coaster goes uphill, the height h increases and the roller coaster gains gravitational potential energy.

2) The relationship between potential and kinetic energy is:

M.E.=K.E.+G.P.E.

where ME is the total mechanical energy, KE is the kinetic energy, GPE is the gravitational potential energy. Since the value of ME is constant (when no friction is present), this means that when KE increases, GPE decreases, and vice-versa.

3) If friction is removed from the track, the roller coaster would move forever. In fact, in the equation written in part 2), ME is constant only in case there is no friction - when friction is present, part of the energy is lost due to the friction, so the total ME available decreases little by little until it becomes zero, and the roller coaster cannot move anymore.

4) It matters because it affects the magnitude of the friction. In fact, friction is given by

F=\mu mg

where \mu is the coefficient of friction, m is the mass ,and g the gravitational acceleration. When the number of carts is increased, the mass increases, therefore the friction increases as well.

4 0
3 years ago
Read 2 more answers
g HW 5.6.The Moon and the Earth both orbit the center of mass of the Earth-Moon system.Earth is 81 times more massive than the M
Law Incorporation [45]

Answer:

R_{cm}  = 4.688 106 m

Explanation:

The expression for the center of mass is

       R cm = 1 / M ∑ r_{i} m_{i}

Where M is the total mass of the system, ri and m1 are the distance and mass of each particle from a defined origin

Let's look for the total mass, the mass of the moon is m and that of the earth Me

    M = M_{e} + m

    M = 81m + m

    M = 82 m

The distance from the earth to the moon is R = 384.4 106 m

    R_{cm} = 1 / M (M R1 + m R)

   R_{cm}  = 1 / 82m (0 + m R)

    R_{cm}  = R / 82

   R_{cm}  = 384.4 106/82

   R_{cm}  = 4.688 106 m

The radius of the earth is

    R_{e} = 6371 103 m

    R_{e}  = 6.371 106 m

We can see that the center of mass of the system is within the beating radius

6 0
3 years ago
Other questions:
  • What do you predict would happen if a person did aerobic exercise but did not work to build muscle?
    15·1 answer
  • A circular loop of wire having a radius of 5.58 cm carries a current of 0.230 A. A vector of unit length and parallel to the dip
    6·1 answer
  • An object is oscillating on a spring with a period of 4.60 s. At time t = 0.00 s the object has zero speed and is at x = 8.30 cm
    15·1 answer
  • In the 1950s, while demand for lumber was high, the Great Cloudy Mountains were wiped clean of trees. Today, an effort to grow b
    6·1 answer
  • A student is using a frequency generator set to 440 Hz. Another student has an identical generator playing an unknown frequency.
    15·1 answer
  • A Gaussian surface in the form of a hemisphere of radius R = 5.51 cm lies in a uniform electric field of magnitude E = 1.08 N/C.
    11·1 answer
  • A light string is wrapped around the edge of the smaller disk, and a 1.50 kgkg block is suspended from the free end of the strin
    15·1 answer
  • How is gravity "best" described?
    5·2 answers
  • I need help with nine and 10 I will really appreciate it
    10·1 answer
  • Physics 13
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!