Total internal energy change is equals to -44.83kJ
Q=-73.2kJ (negative sign indicates that heat was released by the system),
P= 50.0atm
ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)
ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre
work done by the system (w)= -PΔV
w= -(50.0×(-5.60)) atm×litre= 280atm litre
1 atm litre= 101.325J
w= 280 ×101.325 J= 28,371J
1kJ=1000J,
w=28.37KJ,
so putting in the values in equation (1)...
energy change(ΔU) = -73.2 kJ + 28.37 kJ
= - 44.83 kJ
The number of C atoms in 0.524 moles of C is 3.15 atoms.
The number of molecules in 9.87 moles is 59.43 molecules.
The moles of Fe in 1.40 x atoms of Fe is 0.23 x
The moles of in 2.30x molecules of is 3.81.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
A. The number of C atoms in 0.524 mole of C:
6.02214076 × x 0.524 mole
3.155601758 atoms =3.155 atoms
B. The number of molecules in 9.87 moles of :
6.02214076 × x 9.87
59.4385293 molecules= 59.43 molecules
C. The moles of Fe in 1.40 x atoms of Fe:
1.40 x ÷ 6.02214076 ×
0.2324754694 x moles.
0.23 x moles.
D. The moles of in 2.30x molecules of :
2.30x ÷ 6.02214076 ×
3.819239854 moles=3.81 moles
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compound name compound formula elements present
water H2O hydrogen (H) and oxygen (O)
ammonia NH3 nitrogen (N) and hydrogen (H)
carbon monoxide CO carbon (C) and oxygen (O)
carbon dioxide CO2 carbon (C) and oxygen (O)
Answer:
Q = 8.68 × 10⁴ J
Explanation:
We can calculate the heat required to melt a mass of ice, that is, to change it from the solid phase to the liquid phase, at a constant temperature of 0 °C, using the following expression.
Q = ΔH°f × m
where,
- ΔH°f is the standard enthalpy of fusion (ΔH°f for water: 334 J/g)
Q = ΔH°f × m
Q = 334 J/g × 260 g
Q = 8.68 × 10⁴ J