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tatuchka [14]
3 years ago
8

What is the element presented, in this compound?

Chemistry
2 answers:
DerKrebs [107]3 years ago
4 0

compound name compound formula elements present

water H2O hydrogen (H) and oxygen (O)

ammonia NH3 nitrogen (N) and hydrogen (H)

carbon monoxide CO carbon (C) and oxygen (O)

carbon dioxide CO2 carbon (C) and oxygen (O)

kondaur [170]3 years ago
4 0

Answer:

The compound contains carbon. Carbon present in the compound reacts with baric hydroxide solution to form a cloudy solution of baric carbonate.

The observation indicates the presence of sulfur in the compound. Sulfur reacts with sodium nitroprusside solution to give a violet solution.

The yellow precipitate obtained is that of ammonium phosphomolybdate. Hence, the compound contains phosphorus.

Explanation:

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3 years ago
Lauryl alcohol is a nonelectrolyte obtained from coconut oil and is used to make detergents. A solution of 8.80 g of lauryl alco
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Answer:

The molar mass of lauryl alcohol is approximately 180 g/mol

Explanation:

Step 1: Data given

Mass of lauryl alcohol = 8.80 grams

Mass of benzene = 0.100 kg = 100 grams

Freezing point of Benzene is 5.5 °C

Kf value for benzene = 5.12 °C/molal

Step 2: Calculate the freezing point depression

ΔTf = 5.5 - 3.0 °C = 2.5 °C

Step 3: Calculate molality

⇒ with ΔTf = the freezing point depression = 2.5 °C

⇒ with i = the van't Hoff factor = 1

⇒ with kf = the free point depression constat pf benzene = 5.12°C/m

⇒ with m =the molality = TO BE DETERMINED

molality = ΔTf / kf

molality = 2.5 °C / 5.12 °C /m

molality =  0.488 molal

Step 4: Calculate moles lauryl alcohol

Molality = moles lauryl alcohol / mass benzene

Moles lauryl alcohol = molality * mass benzene

Moles lauryl alcohol = 0.488 m * 0.100 kg

Moles lauryl alcohol = 0.0488 moles

Step 5: Calculate molar mass of lauryl alcohol

Molar mass lauryl alcohol = mass lauryl alcohol/ moles lauryl alcohol

Molar mass lauryl alcohol = 8.80 grams / 0.0488 moles

Molar mass lauryl alcohol = 180 g/mol

The molar mass of lauryl alcohol is approximately 180 g/mol

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