All categories

3 years ago

Two liquids- one polar, one nonpolar- have the same molar mass. Which one has the higher boiling point?

Chemistry

2 answers:

victus00 [196]3 years ago

8 0

Answer:

D. the polar liquid will have the higher boiling point, since its molecules have dipole-dipole interactions.

Explanation:

<em>Dipole-Dipole interactions</em> take place only between polar molecules.

They consist of attractions between the negative end of a polar molecule and the positive end of another polar molecule. For example, between the O atom and the H atom in water.

These attractions are not present in a non-polar liquid, so its molecules will be more loosely held together and its boiling point will be lower.

Amanda [17]3 years ago

4 0

Answer: d. the polar liquid will have the higher boiling point, since its molecules have dipole-dipole interactions.

Explanation:

You might be interested in

0.71 g Cu equals how many moles

Norma-Jean [14]

The correct answer is 0.011330374846536 Hope this helps ;D

5 0

3 years ago

Read 2 more answers

Arrange these elements based on their atomic radii. ga, f, s, as

mamaluj [8]

please have look at Periodic table , you will solve it yourself !

5 0

3 years ago

Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a

kiruha [24]

From the calculation, the molar mass of the solution is 141 g/mol.

<h3>What is the molar mass?</h3>

We know that;

ΔT = K m i

K = the freezing constant

m = molality of the solution

i = the Van't Hoft factor

The molality of the solution is obtained from;

m = ΔT/K i

m = 3.89/5.12 * 1

m = 0.76 m

Now;

0.76 = 26.7 /MM/0.250

0.76 = 26.7 /0.250MM

0.76 * 0.250MM = 26.7

MM= 26.7/0.76 * 0.250

MM = 141 g/mol

Learn more about molar mass:brainly.com/question/12127540?

#SPJ12

5 0

2 years ago

A mixture of methanol and methyl acetate contains 15.0 wt% methanol.

Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

$\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol$

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

$\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol$

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

$\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h$

5 0

3 years ago

An unknown substance has the following properties:

Anastasy [175]

Answer:

Homogenous mixture

Explanation:

Homogenous mixtures like ice cream appear to be uniform, and you cannot see their individual components.

6 0

3 years ago

Read 2 more answers