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3 years ago

An apple pudding is prepared by combining apples, sugar, butter, and lemon juice. To which category does it belong?

2 answers:

8 0

The answer is B) Mixture. Compound is a substance with a fixed ratio of atoms, Like Fe2O3, all the pure compounds of Fe2O3 will have the same composition: 2 parts of element Fe and 3 parts of element O. Mixture is not homogeneous, this is its composition is not uniform. As you can see two different pies will have different compositions, even though you try that they are equal.

exis [7]3 years ago

3 0

B)mixture they need to be mixed

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Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad

S_A_V [24]

Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M

3 0

3 years ago

How many protons does the neutral atom pictured have? A) 8 B) 18 C) 2 D) 20

Shalnov [3]

Answer:

b 18

Explanation:

3 0

3 years ago

Read 2 more answers

Helppppppppppp!!!!!!!!

Natali5045456 [20]

Pressure does not affect the voltage produced in a voltaic cell.

8 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m

Bond [772]

Answer:

$m_{H_2O}=4.86gH_2O$

Explanation:

Hello,

In this case, the described chemical reaction is:

$C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O$

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

$n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6$

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

$n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6$

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

$m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O$

Best regards.

3 0

3 years ago

If a nucleus of an atom has 12 protons, how many electrons are there

harkovskaia [24]

If its sodium it would have 11 electrons

7 0

3 years ago