1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
masha68 [24]
2 years ago
8

An apple pudding is prepared by combining apples, sugar, butter, and lemon juice. To which category does it belong?

Chemistry
2 answers:
Natalija [7]2 years ago
8 0
<span>The answer is B) Mixture. Compound is a substance with a fixed ratio of atoms, Like Fe2O3, all the pure compounds of Fe2O3 will have the same composition: 2 parts of element Fe and 3 parts of element O. Mixture is not homogeneous, this is its composition is not uniform. As you can see two different pies will have different compositions, even though you try that they are equal.</span>
exis [7]2 years ago
3 0
B)mixture they need to be mixed

You might be interested in
Which is a series circuit and a parallel circuit
kirza4 [7]

Explanation:

A is a series circuit

B is parallel circuit

8 0
3 years ago
Read 2 more answers
How are sound waves can be used for various applications
kykrilka [37]

Answer:

Sound waves are used for measurement in hertz.

Explanation:

6 0
3 years ago
In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h
LuckyWell [14K]

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 =  $ 32.85

(b) Cost of electricity for 0.025 W  fluorescent  bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

6 0
3 years ago
Cinnamon owes its flavor and odor to cinnamaldehyde (C9H8O). Determine the boiling point elevation of a solution of 92.7 mg of c
Flauer [41]

Answer:

The boiling point elevation is 3.53 °C

Explanation:

∆Tb = Kb × m

∆Tb is the boiling point elevation of the solution

Kb is the molal boiling point elevation constant of CCl4 = 5.03 °C/m

m is the molality of the solution is given by moles of solute (C9H8O) divided by mass of solvent (CCl4) in kilogram

Moles of solute = mass/MW =

mass = 92.7 mg = 92.7/1000 = 0.0927 g

MW = 132 g/mol

Moles of solute = 0.0927/132 = 7.02×10^-4 mol

Mass of solvent = 1 g = 1/1000 = 0.001 kg

m = 7.02×10^-4 mol ÷ 0.001 kg = 0.702 mol/kg

∆Tb = 5.03 × 0.702 = 3.53 °C (to 2 decimal places)

6 0
3 years ago
when the sum 4.9965 + 2.11 + 3.887 is calculated, to how many decimal places should the answer be reported?
jarptica [38.1K]

Answer:

the correct answer is four decimal places

3 0
3 years ago
Other questions:
  • How many atoms are present in 4.0 Mol of sodium
    10·1 answer
  • 0.052301 km significant figures
    6·1 answer
  • Are these right? Please help
    11·1 answer
  • A single glucose molecule produces about 38 molecules of ATP through the process of cellular respiration. However, this only rep
    8·1 answer
  • 1 mole of a gas occupies 22.4 L at ________
    10·1 answer
  • Explain, in terms of ions, why the ability to conduct an electric current is greater for the
    11·1 answer
  • Which of these best describes the relationship between smoke from factories and acid
    12·2 answers
  • The scientific method is a that can be used to answer any . The process begins when a scientist makes an . Then, they do to lear
    7·1 answer
  • For the readion 2Na + Ch&gt; 2NaCl, how many grams of Ch are required to read completely with 450 g Na
    14·1 answer
  • Given the following equation: 2h20=2h2+02 how many grams of o2 are produced if 3.6 grams of h20 react?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!