Solve for x. 4 5 (15x+20)−7x= 5 6 (12x−24)+6

Solve the following system of equations. -3x + 5y = 80 x + 5y = 40 A. x = -10, y = 10 B. x = 2, y = 17.2 C. x = 8, y = 6.4 D. x

hammer [34]

-3x+5y=80 if the x = -10 and y = 10
x+5y=40 if the x= -10 and y= 10

5 0

3 years ago

[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd

Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 $\frac{f(x+h)-f(x)}{h}$

Now, for the purpose of the function, we need this:

Then we will have:

$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0

9 months ago

One serving of Mike’s crackers has 150 calories and a mass of 30 grams. How many calories are in 6 grams of the crackers?

Elodia [21]

$\bf \begin{array}{ccll}
calories&grams\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
150&30\\
c&6
\end{array}\implies \cfrac{150}{c}=\cfrac{30}{6}\implies \cfrac{150\cdot 6}{30}=c$