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3 years ago

Every force has one and only one 3rd law pair force.

Physics

2 answers:

viktelen [127]3 years ago

5 0

Answer: Please see below as the answer is self-explanatory.

Explanation:

The Newton's 3rd law, in simple words, explains, that for any force exerted on an object by another one, there exists a reaction from the object acted upon, which consists in another force, that is of equal value that the one is being exerted on it, but in the opposite direction, and is acting on the the other object.

So, Newton's 3rd Law says that for any pair of objects interacting, there is a pair of forces, equal and opposite, that each of them exerts on the other.

It is very important to understand, that in any free body diagram, it must be showed only one of these forces, the reaction that the other object is exerting on the object for which we are drawing the FBD, not the two forces, as the another one is external to the other object.

One example for this is the normal force, the gravity force, etc.

FromTheMoon [43]3 years ago

3 0

Answer:

Explanation:

This statement is true. According to Netwon's third Law, every force has one and only same and opposite force as reaction.

Actually, the two forces must be originated in two physical points, which act in opposite direction with equal magnitude. The best example of this the force due to gravity and the normal force, which is the unique pair reaction force of the one due gravity.

Therefore, the given statement is true.

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What are the differently types of motion in a bicycle?

Ksivusya [100]

The two types of motion exerted in bicycle are:
1. rotary motion
2. linear motion

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3 years ago

A wave in which particles of the medium move at right angles to the direction of the wave is called a

Licemer1 [7]

Answer:

transverse wave: A wave in which particles of the medium move at right angles to the direction of the wave is called a transverse wave.

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3 years ago

A car is driving down the highway at a 50 m/s. Suddenly, the driver sees an accident and slams on his breaks, coming to a comple

vlada-n [284]

Given parameters:

Speed of the car = 50m/s

Time = 10s

Unknown:

Distance traveled before the car stopped = ?

We need to establish speed - time - distance relationship.

Speed is the rate of change of distance with time. It is a scalar quantity .

Mathematically;

Speed = $\frac{distance}{time}$

Distance = speed x time

Input the parameters and solve;

Distance = 50 x 10 = 500m

The car traveled 500m before it stopped.

4 0

3 years ago

Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass

kirza4 [7]

Answer:

a. 0.342 kg-m² b. 2.0728 kg-m²

Explanation:

a. Since the skater is assumed to be a cylinder, the moment of inertia of a cylinder is I = 1/2MR² where M = mass of cylinder and r = radius of cylinder. Now, here, M = 56.5 kg and r = 0.11 m

I = 1/2MR²

= 1/2 × 56.5 kg × (0.11 m)²

= 0.342 kgm²

So the moment of inertia of the skater is

b. Let the moment of inertia of each arm be I'. So the moment of inertia of each arm relative to the axis through the center of mass is (since they are long rods)

I' = 1/12ml² + mh² where m = mass of arm = 0.05M, l = length of arm = 0.875 m and h = distance of center of mass of the arm from the center of mass of the cylindrical body = R/2 + l/2 = (R + l)/2 = (0.11 m + 0.875 m)/2 = 0.985 m/2 = 0.4925 m

I' = 1/12 × 0.05 × 56.5 kg × (0.875 m)² + 0.05 × 56.5 kg × (0.4925 m)²

= 0.1802 kg-m² + 0.6852 kg-m²

= 0.8654 kg-m²

The total moment of inertia from both arms is thus I'' = 2I' = 1.7308 kg-m².

So, the moment of inertia of the skater with the arms extended is thus I₀ = I + I'' = 0.342 kg-m² + 1.7308 kg-m² = 2.0728 kg-m²

5 0

3 years ago

A person walks first at a constant speed of 5.40 m/s along a straight line from point to point and then back along the line from

rosijanka [135]

Answer: The average speed over the entire trip is 3.94 m/s

Explanation:

As we know : $speed=\frac{distance}{time}$