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jenyasd209 [6]
3 years ago
8

Which of these surfaces gives unpolarized reflected light?

Physics
2 answers:
barxatty [35]3 years ago
5 0

Answer:

Metal

Explanation:

Light is basically an electromagnetic wave having both electric and magnetic component. This contains electric charges. While traveling, EM wave vibrates in multiple planes. This light is unpolarized light. The process of limiting the vibrations to a single plane is called as polarization.

This can be achieved through non metallic reflection (Snow and Glass), refraction (Water), scattering, and Polaroid filters. A metallic reflection will not result in polarization.

scoray [572]3 years ago
4 0

The answer is Metal I'm 100% positive

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Top speed = Vf, initial speed = Vi
time (t) = V(Vf-Vi) ÷ a
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When an object radiates heat, the strength of this radiation far from the object decreases when distance from the source increas
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What is the frequency of a wave that has a wavelength of 2000 meters and is traveling at 20 m/s?
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An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.
Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{water}

F_{b}=79.1-21.8

F_{b}=57.3\ N

F_{b}=\rho g h

Put the value into the formula

57.3=1000\times V\times 9.8

V=\dfrac{57.3}{1000\times9.8}

V=5.84\times10^{-3}\ m^3

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho Vg

79.1=\rho\times5.84\times10^{-3}\times9.8

\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}

\rho=1382\ kg/m^3

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{oil}

F_{b}=79.1-48.4

F_{b}=30.7\ N

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho_{oil} Vg

30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8

\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}

\rho=536.4\ kg/m^3

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0
3 years ago
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