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wariber [46]
3 years ago
9

g A thin uniform film of oil that can be varied in thickness covers a sheet of glass of refractive index 1.52. The refractive in

dex of the oil is 1.64. Light of wavelength 555 nm is shone from air at normal incidence on the film. Starting with no oil on the glass, you gradually increase the thickness of the oil film until the first interference maximum in the reflected light occurs. What is the thickness of the oil film at that instant
Physics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

The right solution is "84.09 nm".

Explanation:

The given values are:

Refractive index of glass,

= 1.52

Refractive index of oil (n),

= 1.64

Wavelength (λ),

= 555 nm

Now,

The thickness of the film (t) will be:

= \frac{\lambda}{4n}

= \frac{555}{4\times 1.65}

= \frac{555}{6.6}

= 84.09 \ nm

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For the first one 320

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