Will this one work?...................
Answer:
a average load current = 11.33 A
b rms load current = 8.02A
c true power =962.64 W
d apparent power =962.64 W
e. power factor cosθ =1
Explanation:
Vs (t) = 170 sin(377t) v
Vm =170v
Vrms = 170/√2 =120.23 v
Im = Vm/R = 170/15 = 11.33 A
Irms = Im/ √2 = 11.33/√2 =8.02A
Resistors are electronic components that consume energy
the power in a resistor is given by P =IVcosθ ; in a resistor cosθ =1
P =IV
The electrical power consumed by a resistance, (R) is called the true or real power
and is obtained by multiplying the rms voltage with the rms current.
P= Vrms × Irms
120.03×8.02
P= 962.64 W ; true power
apparent power = Vrms × Irms
=120.03×8.02
= 962.64W ; apparent power
power factor cosθ = true power/ apparent power
cosθ = 962.64/962.64
cosθ = 1
For the purely resistive circuit, the power factor is 1 , because the reactive power is equal to zero (0).
Answer:
6692J
Explanation:
Power is defined as the rate at which work is being done.
So,
Power = 
Work done = Power x time
Given parameters:
Power = 478watts
Time = 14s
So;
Work done = 478 x 14 = 6692J
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