Answer:
Option (d) chlorine has a greater ionization energy than sodium
Explanation:
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. Sodium has just 1 electron in it's outmost shell and chlorine has 7.
Sodium needs 7 electrons to complete it's octet configuration and chlorine needs just 1.
Sodium can not attract 7 electrons to complete it's octet configuration instead it will easily lose the 1 electron in it's outmost shell to form cation. On the other hand, it will be difficult for chlorine to lose any of it's outmost electrons. This makes chlorine to have higher ionization energy than sodium.
Answer:
The correct answer is (D) All of the above.
Explanation:
A chemical bond is the attraction force between atoms (covalent bond) or between oppositely charged ions (ionic bond) to form a stable arrangement. In order to get a stable arrangement must be fulfilled the octet rule. This establishes that an atom could share (covalent bond) win or lose (ionic bond) electrons with other atoms till every atom has eight valence electrons. The complete outer shell of valence electrons make elements stable to get a stable noble gas configuration.
Answer:
474.64mmHg
Explanation:
From the question given, we obtained the following:
V1 = 10L
P1 = 655mmHg
V2 = 13.8L
P2 =?
P1V1 = P2V2
10 x 655 = P2 x 13.8
Divide both side by the coefficient P2 i.e 13.8
P2 = (10 x 655) / 13.8
P2 = 474.64mmHg
Therefore, the new pressure will be 474.64mmHg
Answer:
0.07172 L = 7.172 mL.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 1.0 atm, Standard P).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 3.2 x 10⁻³ mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 273 K, Standard T).
<em>∴ V = nRT/P =</em> (3.2 x 10⁻³ mol)(0.0821 L.atm/mol.K)(273 K)/(1.0 atm) = <em>0.07172 L = 7.172 mL.</em>
<span>The correct answer is 'freezing point depression'. Colligative properties depend on the concentration of molecules of a solute. Examples of other colligative properties are boiling point elevation or vapour pressure lowering. The salt causes ice on the side walk to melt because it lowers the freezing point. </span>
