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4 years ago

(2.92 x 10^3)(6.14 x 10^5)

Chemistry

1 answer:

mariarad [96]4 years ago

4 0

The answer is 1792880000

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The increase in the rate of solvation with a rise in solvent temperature is mainly due to a(n)

katrin2010 [14]

The answer would be b

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3 years ago

Wich of the following does not directly affect the weather

Drupady [299]

Answer:

Tings that effect weather is basically the following:

Distance from sea
Altitude
Distance to the equator or poles.
Mountains
Jet streams,etc

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3 years ago

Draw the lewis structure for phosphoryl chloride. optimize formal charges.

attashe74 [19]

Answer: Connect the atoms with single bonds. The less electronegative is the phosphorous atom. Hence, the P atom is going to be the central atom. Recall that electronegativity decreases as we move away from the fluorine atom in the periodic chart. Simple method for drawing Lewis dot structures

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3 years ago

Consider the intermediate chemical reactions. 2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one ha

DochEvi [55]

Answer: When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

$CaO(s)+CO_2\rightarrow CaCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)$ $\Delta H_1=-812.8kJ$

(2) $2Ca(s)+O_2(g)\rightarrow 2CaO(s)$ $\Delta H_2=-1269kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]$

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

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3 years ago

Compute the freezing point of this solution:

likoan [24]

Answer:

Freezing point = 1.25

Explanation:

If we increase the concentration of the solution, the concentration of H+ does not change.

Convert 2.5% in to decimal

2.5% = 2.5 ÷100

= 0.025

The freezing point = 0.025 × 50

= 1.25

8 0

3 years ago