Answer:
H_w = 2.129 m
Explanation:
given,
Width of the weir, B = 1.2 m
Depth of the upstream weir, y = 2.5 m
Discharge, Q = 0.5 m³/s
Weir coefficient, C_w = 1.84 m
Now, calculating the water head over the weir
now, level of weir on the channel
H_w = y - H
H_w = 2.5 - 0.371
Height at which weir should place is equal to 2.129 m.
Part b)
Part a)
As we know that impulse is due to the force applied for small time due to which momentum is changed
so we will have
also we know that
now impulse is given as
As we know that
Solar energy is energy that is produced using the sun's rays.
334 m/s
velocity = frequency x wavelength
velocity = 3.34 x 100 = 334 m/s