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2 years ago

An object is 10. cm from the mirror, its height is 3.0 cm, and the focal length is 2.0 cm. What is the distance from the

Physics

1 answer:

Rashid [163]2 years ago

4 0

The distance from the image to the mirror is C) 2.5 cm

Explanation:

A mirror is an object that reflects the light coming from an object, creating an image of the object itself.

We can solve this problem by using the mirror equation, which states that:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f is the focal length of the mirror

p is the distance between the object and the mirror

q is the distance between the image and the mirror

For the situation in this problem, we have:

f = 2.0 cm is the focal length of the mirror

p = 10.0 cm is the distance of the object from the mirror

Solving for q, we find:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{2.0}-\frac{1}{10}=\frac{4}{10}\\\rightarrow q=\frac{10}{4}=2.5 cm$

Learn more about reflection and other wave phenomena:

brainly.com/question/3183125

brainly.com/question/12370040

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3 years ago

The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp

IRISSAK [1]

Answer:

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Explanation:

From the question we are told that

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The length is $L = 0.35 \ m$

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Generally the force acting on the tibia is mathematically represented as

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Now this force can also be mathematically represented as

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$k = \frac{E * A }{L}$

substituting values

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Since the tibia support half the weight then the force experienced by the tibia is

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From the above equation the extension (compression) is mathematically represented as

$\Delta L = \frac{ F_k * L }{ A * E }$

substituting values

$\Delta L = \frac{ 375 * 0.35 }{ (2.9 *10^{-4}) * 1.4*10^{10} }$

$\Delta L = 3.2323 *10^{-5} \ m$

From the above equation the maximum force is

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$F = 3750.28 \ N$

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