1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kipiarov [429]
3 years ago
11

An object is 10. cm from the mirror, its height is 3.0 cm, and the focal length is 2.0 cm. What is the distance from the

Physics
1 answer:
Rashid [163]3 years ago
4 0

The distance from the image to the mirror is C) 2.5 cm

Explanation:

A mirror is an object that reflects the light coming from an object, creating an image of the object itself.

We can solve this problem by using the mirror equation, which states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where:

f is the focal length of the mirror

p is the distance between the object and the mirror

q is the distance between the image and the mirror

For the situation in  this problem, we have:

f = 2.0 cm is the focal length of the mirror

p = 10.0 cm is the distance of the object from the mirror

Solving for q, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{2.0}-\frac{1}{10}=\frac{4}{10}\\\rightarrow q=\frac{10}{4}=2.5 cm

Learn more about reflection and other wave phenomena:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

You might be interested in
Can an object be accelerated while traveling at constant velocity? Why or why not?
AysviL [449]

Answer:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. If an object's velocity is constant, however, its acceleration will be zero.

3 0
3 years ago
Please help!!!!
Dafna11 [192]

The intensity of the electric field is 30,000 N/C

Explanation:

The strength of the electric field produced by a single-point charge is given by the equation

E=k\frac{q}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

q=3\cdot 10^{-9}C is the magnitude of the charge

r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity

Substituting, we find:

E=(8.99\cdot 10^9)\frac{3\cdot 10^{-9}}{(0.03)^2}=30,000 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
14
Minchanka [31]

Answer:

C

Explanation:

8 0
2 years ago
Read 2 more answers
A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?​
Delicious77 [7]

Answer: 5.8 m/s squared

Explanation: just got that question lol

4 0
2 years ago
A train travels 160 km in 2 h. What is the train’s average speed in km/h?
loris [4]
The train’s average speed is 80km/h
3 0
3 years ago
Read 2 more answers
Other questions:
  • Which of newtons laws is illustrated by a squid moving forward by shooting water out behind it? Why?
    15·1 answer
  • The outer planets _____.all have rings
    9·2 answers
  • A "gauge 8" jumper cable has a diameter d of 0.326 centimeters. The cable carries a current I of 30.0 amperes. The electric fiel
    12·1 answer
  • I dont understand physics.
    11·1 answer
  • When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot
    12·1 answer
  • Un Esquiador Inicia un Salto Horizontal con una velocidad Inicial de 25 m/s. La Altura al Final de la Rampa es de 80 m del punto
    15·1 answer
  • Which of these forms due to the force of compression?
    12·2 answers
  • if you poured oil and water into a beaker , which liquid would be on top and which would be on the bottom ? How would the densit
    7·1 answer
  • Haha jk thats really funny that it doesnt let you take down questions
    5·2 answers
  • Is quartzite a mineral, a rock, or neither?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!