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Airida [17]
4 years ago
12

Atomic emission spectroscopy and the method of standard addition are used to determine the Na+ concentration and its uncertainty

in an unknown sample. Increasing amounts of a 1.75 μg/mL standard Na+ solution are added to a series of volumetric flasks containing 15.00 mL of the unknown solution. The volumetric flasks are then diluted to a final volume of 200.0 mL. Atomic emission spectroscopy is then used to measure the emission intensity of each solution.
Chemistry
1 answer:
Bess [88]4 years ago
5 0

Answer:

atomic nuts are INCREDIBLE

Explanation:

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Find the equation of the line passing through the points (2, 1) and (5, 10).​
Vedmedyk [2.9K]

The equation : y=3x-5

<h3>Further explanation </h3>

Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates

General formula

y-y1 = m(x-x1)

or

y = mx + c

Where

m = straight-line gradient which is the slope of the line

x1, y1 = the Cartesian coordinate that is crossed by the line

c = constant

The formula for a gradient (m) between 2 points in a line

m = Δy / Δx

  • Gradient

\tt \dfrac{10-1}{5-2}=3

  • Equation

\tt y-1=3(x-2)\\\\y-1=3x-6\\\\y=3x-5

3 0
3 years ago
For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
Alexxx [7]
<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
A piece of aluminum weighing 10.0 grams is placed into a graduated cylinder that has an initial volume (before immersion) of 35.
padilas [110]

Answer:

The density of the metal sample is 2.70 \frac{grams}{mL}

Explanation:

Density is a magnitude that allows you to measure the amount of mass in a given volume of a substance. Then, the expression for the calculation of density is the ratio between the mass of a body and the volume it occupies:

d=\frac{m}{V}

Density, according to the International System of Units, is usually expressed in kilograms per cubic meter (kg / m3) or gram per cubic centimeter (g / cm3). Although it can also be expressed in any other unit of mass by volume.

So, for the calculation of density you know that:

  • mass of the sample= 10 grams
  • volume of the sample = volume on the cylinder after immersion - volume on the cylinder before immersion= 38.7 mL - 35.0 ml = 3.7 mL

Then:

d=\frac{10 grams}{3.7 mL}

d=2.70 \frac{grams}{mL}

<u><em>The density of the metal sample is 2.70 </em></u>\frac{grams}{mL}<u><em></em></u>

5 0
3 years ago
The data set gives the number of bottles filled by each of the workers in a bottling plant in one day
Tcecarenko [31]
37.5 for median ( first organize from least to greatest, elimate from each side until you get to center then add two numbers and divide by two.) Hope that helps.
6 0
3 years ago
Your teacher asked you to identify the stage of mitosis of a specimen under the microscope. You observed that instead of a typic
yKpoI14uk [10]

Answer:

D. Cytokinesis

Explanation:

Mitosis is the cell division that involves the synthesis of two genetically identical daughter cells. Mitotic division occurs in stages namely: prophase, metaphase, anaphase and telophase. Following this four processes is another called CYTOKINESIS

Cytokinesis, which occurs after nuclear division, is the division of the cytoplasm. According to this question, the observation made when viewing the specimen was that "the cell has a narrow middle part which almost separates into two bulging ends and which looks like the number 8". This described the process of CYTOKINESIS in plant cell specifically.

7 0
3 years ago
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