Question

Kayden is working two summer jobs, making $19 per hour lifeguarding and making $9 per hour walking dogs. In a given week, he can work no more than 20 total hours and must earn no less than $270. If xx represents the number of hours lifeguarding and yy represents the number of hours walking dogs, write and solve a system of inequalities graphically and determine one possible solution.

Answer 1

Answer:

Kayden spends 15 hours lifeguarding and 3 hours walking dogs

Graph is attached.

Step-by-step explanation:

Given: x represents the number of hours lifeguarding and y represents the number of hours walking dogs.

Kayden is asking $19 per hour lifeguarding and making $9 per hour walking dogs

To find: system of inequalities graphically and one possible solution

Solution:

As Kayden can work no more than 20 total hours,

$x+y\leq 20$

As Kayden must earn no less than $270,

$19x+9y\geq 270$

Graph of both the inequalities are attached.

Red part denotes $x+y\leq 20$ and blue part denotes $19x+9y\geq 270$

Solution is marked as $(15,3)$ .

So, Kayden spends 15 hours lifeguarding and 3 hours walking dogs.

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