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2 years ago

Who discovered the law of conservation of energy?

Physics

2 answers:

BlackZzzverrR [31]2 years ago

6 0

Answer:

Julius Robert Mayer in 1842

Explanation:

weqwewe [10]2 years ago

5 0

Julius Robert Mayer discovered the Law of Conservation of Energy.

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Why is the moon tilted

butalik [34]

It’s cause by the fact that the earth is tilted 23.5 degrees

8 0

2 years ago

Which statement best defines inertia? An object's motion is unaffected by any external forces acting upon it. An object responds

svetoff [14.1K]

Answer:

An object responds to a force by tending to move in the direction of that force

Explanation:

The inertia of a body can be defined with the help of Newton's second law

F = m a

Where F is the applied force, a is the acceleration of the body and m is the mass

the force and the acceleration are vectors that point in the same direction and m is a scalar constant that relates the two vectors, this scalar constant is called masses and it measures the resistance of the bodies to the change of motion.

From the previous statement we see that the statement that best describes inertia is:

An object responds to force by tending to move in the direction of the force.

4 0

3 years ago

Write 4,007,500,000 in scientific notation.

Vika [28.1K]

The answer is 4.0075 x 10^9

7 0

2 years ago

A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t

borishaifa [10]

Answer:

Angular acceleration will be $18.84rad/sec^2$

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity $\omega _i=0rev/sec$

And final angular velocity $\omega _f=24rev/sec$

Time is given as t = 8 sec

From equation of motion

We know that $\omega _f=\omega _i+\alpha t$

$24=0+\alpha \times 8$

$\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2$

So angular acceleration will be $18.84rad/sec^2$

4 0

3 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

3 0

2 years ago