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Andru [333]
3 years ago
13

A jet plane passes over you at a height of 5870 m and a speed of Mach 1.47. (a) Find the Mach cone angle. (b) How long after the

jet passes directly overhead does the shock wave reach you
Physics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

(a) Angle is 42.865°

(b) t=12.54s

Explanation:

The jet plane is at 5870m from Earth surface

The jet traveling at speed of 1.47 Mach

Speed of Sound v=343 m/s

Part (a)

As we know :

Sin\alpha =\frac{v}{vs}\\

Substitute the given values

Sin\alpha =\frac{v}{1.47v}\\ Sin\alpha =\frac{343m/s}{1.47(343m/s)} \\Sin\alpha =0.68027\\\alpha =Sin^{-1}(0.68027)\\\alpha  =42.865^{o}

Angle is 42.865°

Part (b)

As the distance given as:

d=vst

By using some trigonometry

d=\frac{h}{tan\alpha }

Where h is the height of jet plane

Thus

t=\frac{h}{tan\alpha } \frac{1}{vs}

Substitute the given values

So

t=\frac{5870m}{tan(42.865)}\frac{1}{1.47(343m/s)}  \\t=12.54s

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