Answer:
7.72 Liters
Explanation:
normal body temperature = T_body =37° C
temperature of ice water = T_ice =0°c
specfic heat of water = c_{water} =4186J/kg.°C
if the person drink 1 liter of cold water mass of water is = m = 1.0kg
heat lost by body is Qwater =mc_{water} ΔT
= mc{water} ( T_ice - T_body)
= 1.0×4186× (0 -37)
= -154.882 ×10^3 J
here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories
= 286×4186J
so number of liters of ice water have to drink is
n×Q_{water} =Q_{walk} n= Q_{walk}/ Q_{water}
= 286×4186J/154.882×10^3 J
= 7.72 Liters
D
Because the rest of the answers are illogical
Wouldn’t it be 1. resistance is high compared to the voltage and with less resistance, higher current
Answer:
$84
Explanation:
The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.
The heater consumed by the heater is 1200 kWh.
For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:
Electric input to heat pump = 1200 / 2.4 = 500 kWh
That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh
The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh
Money saved = $0.12/kWh * 700 kWh = $84
