Answer:
0.062mol
Explanation:
Using ideal gas law as follows;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821Latm/molK)
T = temperature (K)
Based on the information provided;
P = 152 Kpa = 152/101 = 1.50atm
V = 0.97L
n = ?
T = 12°C = 12 + 273 = 285K
Using PV = nRT
n = PV/RT
n = (1.5 × 0.97) ÷ (0.0821 × 285)
n = 1.455 ÷ 23.39
n = 0.062mol
Answer:
See explanation
Explanation:
The question is incomplete because the image of the alcohol is missing. However, I will try give you a general picture of the reaction known as hydroboration of alkenes.
This reaction occurs in two steps. In the first step, -BH2 and H add to the same face of the double bond (syn addition).
In the second step, alkaline hydrogen peroxide is added and the alcohol is formed.
Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.
Steric hindrance is known to play a major role in this reaction as good yield of the anti-Markovnikov like product is obtained with alkenes having one of the carbon atoms of the double bond significantly hindered.
Chemical change because it cannot be reversed
Answer:
- The percentage of unit cell volume that is occupied by atoms in a face- centered cubic lattice is 74.05%
- The percentage of unit cell volume that is occupied by atoms in a body-centered cubic lattice is 68.03%
- The percentage of unit cell volume that is occupied by atoms in a diamond lattice is 34.01%
Explanation:
The percentage of unit cell volume = Volume of atoms/Volume of unit cell
Volume of sphere = 
a) Percentage of unit cell volume occupied by atoms in face- centered cubic lattice:
let the side of each cube = a
Volume of unit cell = Volume of cube = a³
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 4
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.7405
= 0.7405 X 100% = 74.05%
b) Percentage of unit cell volume occupied by atoms in a body-centered cubic lattice
Radius of atoms = 
Volume of each atom =
=
Number of atoms/unit cell = 2
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.6803
= 0.6803 X 100% = 68.03%
c) Percentage of unit cell volume occupied by atoms in a diamond lattice
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 8
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.3401
= 0.3401 X 100% = 34.01%