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OleMash [197]
3 years ago
15

A solution that is 20% acid and 80% water is mixed with a solution that is 50% acid and 50% water. If twice as much 50% acid sol

ution is used as 20% solution, then what is the ratio of acid to water in the mixture of the solutions?
Chemistry
1 answer:
eduard3 years ago
7 0

Answer:

The ratio acid to water in the mixture is 2:3

Explanation:

Let the volume of 20% acid solution used to make the mixture = x units

So, the volume of 50% acid solution used to make the mixture = 2x units

Total volume of the mixture = x + 2x = 3x units

For 20% acid solution:

C₁ = 20% , V₁ = x

For 50% acid solution :

C₂ = 50% , V₂ = 2x

For the resultant solution of sulfuric acid:

C₃ = ? , V₃ = 3x

Using

<u>C₁V₁ + C₂V₂ = C₃V₃</u>

20×x + 50×2x = C₃×3x

So,

20 + 50×2 = C₃×3

Solving

120 = C₃×3

C₃ = 40 %

Thus, for the resultant mixture,

<u>Acid percentage = 40%</u>

<u>Water percentage = (100 - 40)% = 60%</u>

<u>Ratio acid to water in the mixture = 40:60 = 2:3</u>

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CO2+2H2O=H3O^++HCO3^-
bekas [8.4K]

<u>Answer:</u>

<em>Bronsted Lowry Theory</em>

<em>CO_2 is the acid </em>

<em>H_2 O is the base </em>

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<u>Explanation:</u>

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.  

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.  

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,  

H^++H_2O\Rightarrow H_3O^+

H_3O^+ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example  

Let us consider the example given in the question

CO_2+2H_2 O>H_3 O^+   +HCO_3^- can be written as (removed 1 H_2 O from both the sides )

CO_2+H_2 O>H^++HCO_3^- or  

CO_2+H_2 O  > H_2 CO_3 reversing the equation  

H_2 CO_3+H_2 O>H_3 O^+  +HCO_3^-

H_2 CO_3 is the acid which donates H^+ to form HCO_3^-

H_2 O is the base which gains H^+ to form H_3 O^+

HCO_3^- is the conjugate base and H_3 O^+ is the conjugate acid

So

CO_2 is the acid

H_2 O is the base

H_3 O^+ is the conjugate acid and

HCO_3^- is the conjugate base

(Answer)  

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