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OleMash [197]
3 years ago
15

A solution that is 20% acid and 80% water is mixed with a solution that is 50% acid and 50% water. If twice as much 50% acid sol

ution is used as 20% solution, then what is the ratio of acid to water in the mixture of the solutions?
Chemistry
1 answer:
eduard3 years ago
7 0

Answer:

The ratio acid to water in the mixture is 2:3

Explanation:

Let the volume of 20% acid solution used to make the mixture = x units

So, the volume of 50% acid solution used to make the mixture = 2x units

Total volume of the mixture = x + 2x = 3x units

For 20% acid solution:

C₁ = 20% , V₁ = x

For 50% acid solution :

C₂ = 50% , V₂ = 2x

For the resultant solution of sulfuric acid:

C₃ = ? , V₃ = 3x

Using

<u>C₁V₁ + C₂V₂ = C₃V₃</u>

20×x + 50×2x = C₃×3x

So,

20 + 50×2 = C₃×3

Solving

120 = C₃×3

C₃ = 40 %

Thus, for the resultant mixture,

<u>Acid percentage = 40%</u>

<u>Water percentage = (100 - 40)% = 60%</u>

<u>Ratio acid to water in the mixture = 40:60 = 2:3</u>

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Hope this is correct and helpful

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The answer to your question is:  letter D

Explanation:

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2. The organisms originally lived only in Earth's water.  

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The fossil remains have been discovered in the rocks of all the ages. The simplest organisms fossils are witnessed in the oldest rocks, and the fossils of more composite species are found in the newest rocks. This supports the theory of evolution suggested by Darwin, according to which the simple life forms slowly gets evolved into more composite ones.  

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Explanation:

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Answer:

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