Whenever a vehicle is in motion, it has got kinetic energy. Kinetic energy has a direct relationship with the stopping distance. Kinetic energy is dependent on the mass of the vehicle and also the velocity at which it is traveling. In case of a small vehicle, the mass of the vehicle will be small and so the stopping distance will also be less compared to a large vehicle. In the case of the large vehicle traveling at the same velocity as the small vehicle, the stopping distance will be greater because the large vehicle has a larger mass. So in case of a small vehicle the kinetic energy will be less and so the distance for stopping will be less than that of the large vehicle.
Use the kinematic equation: Vf=Vi+at
Then plug;
Vi=14 m/s
a=5 m/s²
t=20 s. Therefore;
Vf=14+(5*20)
Vf=114 m/s.
Answer:
a= 0.5m/s^2
Explanation:
Force applied on an object is known as
F=m.a (Newton's second law states it)
a=F/m
a=5/10=0.5m/s^2
Answer:
5ms⁻²
Explanation:
Given that,
Initial velocity of car (at t=0) u=0 m/s
Final velocity of car (after 10 sec) v=50 m/s
Time taken (t)= 10 sec.
acceleration(a)=?
now,
v = u + at
at = v-u
a= (v-u) / t
a= (50-0) / 10
a = (50/10)
a=5 ms⁻²