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Irina18 [472]
3 years ago
7

A penny is dropped off the top of the Stratosphere from rest and falls freely with the

Physics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

S = 122.5m

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 5 seconds

Since it's a free fall, initial velocity, u = 0

To find the displacement, we would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

  • S represents the displacement or height measured in meters.
  • u represents the initial velocity measured in meters per seconds.
  • t represents the time measured in seconds.
  • a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

S = 0*5 + \frac {1}{2}*(9.8)*5^{2}

S = 0 + 4.9*25

S = 122.5m.

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His acceleration would decrease

Explanation:

because there is more friction.

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Explain the meaning of the name "black hole". This should be 2-3 sentences. Hint- relate this to density and how it effects thin
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The universe is made up of __________.
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Thousands of galaxies
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<img src="https://tex.z-dn.net/?f=%20%7B.5mv%7D%5E%7B2%7D%20%20%3D%20mgh" id="TexFormula1" title=" {.5mv}^{2} = mgh" alt=" {.5m
Katyanochek1 [597]

You said 0.5 · m · v² = m · g · h

Divide each side by 'm' :  0.5 · v² = g · h

Multiply each side by 2 :  v² = 2 · g · h

Square root each side :   v = √(2 · g · h)

You said that  g = 9.8 m/s²  and  h = 875 units

So  v = √(9.8 m/s² · 875 units)

v = √(8,575 m·unit/s²)

v = 92.6 / s² · √(m · unit)

8 0
3 years ago
A mass of 0.250 kg is attached to a spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the forc
Paha777 [63]

The force constant of the spring is approximately 24.038 newtons per meter.

As we are talking about Simple Harmonic Motion. In this exercise we need to determine the Spring Constant (k), in newtons per meter, from the equation of the Period (T), in seconds, which is described below:

T = 2\pi\cdot \sqrt{\frac{m}{k} } (1)

Where m is the mass of the moving element, in kilograms.

If we know that T = 0.640\,s and m = 0.250\,kg, then the spring constant of the spring is:

0.640 = 2\pi\cdot \sqrt{\frac{0.250}{k} }

\sqrt{\frac{0.250}{k} } \approx 0.102

\frac{0.250}{k} \approx 0.0104

k \approx 24.038\,\frac{N}{m}

The force constant of the spring is approximately 24.038 newtons per meter.

Please see this question related to Simple Harmonic Motion for further details: brainly.com/question/17315536

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3 years ago
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