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2 years ago

9

A student throws a 140 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of

the average force on the wall if the duration of the collision is 0.17 s ?

1 answer:

Vitek1552 [10]2 years ago

3 0

Answer:5.35N

Explanation:

Force is defined as the product of mass of an object and its acceleration.

Acceleration is the change in velocity of an object with respect to time.

Acceleration = velocity/ time = 6.5/0.17 = 38.2m/s²

since F = ma and mass is 140g

140g to kg will be 140/1000 = 0.14kg

F = 0.14× 38.2

F = 5.35N

magnitude of the average force is 5.35N

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Explanation:

From the question we are told that

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and $KE_B$ is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

$KE_B = \frac{1}{2} m v^2$

and $PE_B$ is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

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substituting values

$v = 16.57 m/s$

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$v_f = v + 2 a s$

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$0 = 16.57 + 2 * a * 1.8$

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