Answer:
B. QC > 0; QH < 0
Explanation:
Given that there are two reservoir of energy.
Sign convention for heat and work :
1.If the heat is adding to the system then it is taken as positive and if heat is going out from the system then it is taken as negative.
2. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.
From hot reservoir heat is going out that is why it is taken as negative

From cold reservoir heat is coming inside the reservoir that is why it is taken as positive

That is why the answer will be
,
Answer:
x sin nx = x cos nx
same as
theta / theta x (xsin (nx)) = sin (nx) + (nx) cos (nx)
Λ
![= 550 * 10^{-9}\] m. D = 3.50*10^-6 m.](https://tex.z-dn.net/?f=%20%3D%20550%20%2A%2010%5E%7B-9%7D%5C%5D%20m.%0A%0AD%20%3D%203.50%2A10%5E-6%20m.)

Then you need to find x when n=1
or

≈θ for θ<<1 , so θ=

Then you can find rhe distance of<span> bright fringe from the center:</span>