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3 years ago

If 12 newborn babies are randomly selected, how many different gender sequences are possible?

Mathematics

1 answer:

ki77a [65]3 years ago

3 0

If there are 2 genders it's 2^12, which is 4096

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Consider the system of equations.

Harman [31]

The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:

x = -3, y = 2

The given system of equations:

x + 2y = 1............(1)

-3x - 2y = 5..........(2)

This can be written in matrix form as shown:

$\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Find the determinant of $\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]$

$\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle = 4$

$\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12$

$\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8$

$x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3$

$y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2$

The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:

x = -3, y = 2

Learn more here: brainly.com/question/4428059

3 0

3 years ago

What is the area of this figure?<br><br> _______ square kilometers

Nimfa-mama [501]

Answer:

90 square kilometers

Step-by-step explanation:

1. split the figure in small definite sections

2. find the areas of the smaller sections.

3. find the sum of the areas.

3 0

2 years ago

Read 2 more answers

a groups of 210 children attended a school picnic. only 60 of the children ate. what fraction of the children ate?

Amiraneli [1.4K]

The answer is 60/210.
I hope I'm right
Brainliest please!

5 0

3 years ago

Read 2 more answers

Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

lyudmila [28]

$f(\theta)=10\cos\theta+5\sin^2\theta$

then the derivative is

$f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta$

Critical points occur where $f'(\theta)=0$ . This happens for

$-10\sin\theta+10\sin\theta\cos\theta=0$

$-10\sin\theta(1-\cos\theta)=0$

$\implies-10\sin\theta=0\text{ or }1-\cos\theta=0$

In the first case, we find

$-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi$

In the second,

$1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi$

So all the critical points occur at multiples of $\pi$ , or $n\pi$ . (This includes all the even multiples of $\pi$ .)

3 0

3 years ago

Linear equations assignment:

Daniel [21]

Answer:

20 laps

Step-by-step explanation:

2 times = +1 dollars for Paula, +0.50 dollars for Jacki

Try multiplying it the least amount of times to Paula can have more and so 20 times and Paula will have 20 dollar sand Jacki will have 19.75, therefore she needs to do 20 laps.

6 0

3 years ago