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melamori03 [73]
3 years ago
14

If 12 newborn babies are randomly selected, how many different gender sequences are possible?

Mathematics
1 answer:
ki77a [65]3 years ago
3 0
If there are 2 genders it's 2^12, which is 4096
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What is the probability of rolling a dice and landing on a 4, and
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1/6 and 3/6

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a dice has up to 6 sides making it a 1/6 chance for landing ona four. and then making it a 3/6 chance for landing on a even number

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3 years ago
Are these ratios 1:2 11:16 equivalent
g100num [7]
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Explanation:
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7 0
3 years ago
Read 2 more answers
Two factors whose product is 84 are 12 and _[blank]_.
djyliett [7]

Answer: 7

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You know that a multiplication has the following form:

a*b=c

Where a and b are the factors and c is the product.

2. You know one of the factor, then you can find the second one as following:

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7 0
4 years ago
Please help me in this question
weqwewe [10]
Question is: how many 84s will fit in 5376? Let's think about some easy multiples:

84 * 100 = 8400, so it's too big
84 * 10 = 840, so it might work

84 | 5376 | 10
       -840

84 | 4536 | 10
       -840

84 | 3696 | 10
       -840

84 | 2856 | 10
       -840

84 | 2016 | 10
       -840

84 | 1176 | 10
       -840

84 | 336

We can't fit any more 840 in 336, so we check how many 84s are in 336 and what's the remainder:

84 | 336 | 4
     - 336

So there's no remainder. Now we add all the partial quotients to get the final result:

10 + 10 + 10 + 10 + 10 + 10 + 4 = <u>64

</u>
It's correct, I checked it with calculator. I just hope you'll be able to read something from that, it's quite difficult to do partial dividing with no pencil and paper :)
3 0
3 years ago
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