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beks73 [17]
3 years ago
11

An _____ is a substance that protects vulnerable molecules from free radicals.

Chemistry
1 answer:
Anarel [89]3 years ago
4 0
I believe the correct answer is antioxidant. An antioxidant is a substance that protects vulnerable molecules from free radicals. Antioxidants<span> are man-made or natural substances that may prevent or delay some types of cell damage due to free radicals.</span>
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Does anyone understand what to do for 1 and 2
Allisa [31]
I’m sorry I can barely see the question
3 0
3 years ago
What information is needed to determine the amount of moles in 1.6g of HCL?
alukav5142 [94]

Answer:

Molar mass and Mass

Explanation:

The relationship between mass and number of moles is given as;

Number of moles = Mass / Molar mass

Mass = 1.6 g

Molar mass of HCl = ( 1 + 35.5 ) = 36.5 g/mol

Number of moles = 1.6 g / 36.5 g/mol

Number of moles = 0.0438 mol

8 0
3 years ago
Based on the table, which atom has a charge of –1?<br> 1<br> 2<br> 3<br> 4
Shkiper50 [21]

An electron

there is no table but an electron has a charge of -1

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6 0
3 years ago
The mass of 69Ga is 68.7200 amu . The mass of 71Ga is 70.9200 amu .
CaHeK987 [17]
I'm not sure if what this question is asking but ill be assuming that the average molecular mass is required. An assuming that the abundance of each isotope is 50% the average molecular mass is 69.82 amu. 
7 0
4 years ago
If a temperature increase from 21.0 ∘c to 35.0 ∘c triples the rate constant for a reaction, what is the value of the activation
Airida [17]

Answer:

59.077 kJ/mol.

Explanation:

  • From Arrhenius law: <em>K = Ae(-Ea/RT)</em>

where, K is the rate constant of the reaction.

A is the Arrhenius factor.

Ea is the activation energy.

R is the general gas constant.

T is the temperature.

  • At different temperatures:

<em>ln(k₂/k₁) = Ea/R [(T₂-T₁)/(T₁T₂)]</em>

k₂ = 3k₁ , Ea = ??? J/mol, R = 8.314 J/mol.K, T₁ = 294.0 K, T₂ = 308.0 K.

ln(3k₁/k₁) = (Ea / 8.314 J/mol.K) [(308.0 K - 294.0 K) / (294.0 K x 308.0 K)]

∴ ln(3) = 1.859 x 10⁻⁵ Ea

∴ Ea = ln(3) / (1.859 x 10⁻⁵) = 59.077 kJ/mol.

4 0
3 years ago
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