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quester [9]
3 years ago
14

Why is copper a popular mineral? Is it in danger of depletion? Use details to support your answer.

Chemistry
1 answer:
laila [671]3 years ago
7 0

Answer:

yes it is a danger.Copper doesn't break down in the environment, leading to its accumulation in plants and animals. Absorption of some copper into the body is essential for human health. Acute industrial exposure to copper fumes, dusts or mists can result in chronic copper poisoning.Copper is a mineral and an element essential to our everyday lives. It is a major industrial metal because of its high ductility, malleability, thermal and electrical conductivity and resistance to corrosion. It is an essential nutrient in our daily diet.

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The atmosphere we live in is about 5-9 miles thick, depending on where you are on Earth. It is a mixture of 78% nitrogen, 21% ox
vova2212 [387]

Answerino by Duderino:

The troposphere

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3 years ago
Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?
AURORKA [14]
The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

Therefore, the mole ratio of NH3 to N2 is 4:2 which can be simplified into 2:1
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3 years ago
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A student pours Liquid A through filter paper. the liquid passes through the filter paper, but a residue remains on the filter.
AVprozaik [17]

Answer:

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4 0
2 years ago
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How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

6 0
3 years ago
How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the f
katrin [286]

Answer:

2.79g

Explanation:

8 0
3 years ago
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