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3 years ago

13

Why do clouds usually form high in the air rather than near the earths surface

1 answer:

monitta3 years ago

3 0

<span>"High in the air" is a matter of opinion and perspective. And, clouds do form near the earth's surface, we just call it fog. Clouds are often seen hanging around the top of mountains as well. However, the reason clouds usually form up in the air is clouds are moisture, and the moisture evaporates and rises from the earth to where the air is cooler above the earth surface. The moisture in the air then condenses to from lots of little water droplets that form the clouds. Depending upon the time of year and how warm and mosit the air is and how high and how cold the cold air is depends upon how high and what kind of clouds form.</span>

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olasank [31]

Answer:

84.27 g

Explanation:

<em>How many grams of hydrogen are in 10.45 moles of C₃H₈?</em>

Step 1: Calculate the moles of atoms of hydrogen

The molar ratio of C₃H₈ to H is 1:8.

10.45 mol C₃H₈ × 8 mol H/ 1mol C₃H₈ = 83.60 mol H

Step 2: Calculate the mass corresponding to 83.60 moles of hydrogen

The molar mass of hydrogen is 1.008 g/mol.

83.60 mol × 1.008 g/mol = 84.27 g

4 0

4 years ago

Calculate either [H3O+] or [OH−] for each of the solutions at 25 °C. Solution A: [OH−]=1.55×10−7 M Solution A: [H3O+]= M Solutio

Ahat [919]

Answer: A. $[H_3O^+]=0.64\times 10^{-7}M$

B. $[OH^-]=0.11\times 10^{-5}M$

C. $[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M$

Thus solution B is basic in nature.

Explanation:

pH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH for acidic solutions is less than 7, for basic solutions it is more than 7 and for neutral solutions it is equal to 7.

$pH=-\log [H^+]$

$pOH=-log[OH^-]$

$pH+pOH=14$

or $[H^+][OH^-]=10^{-14}$

A. $[OH^-]=1.55\times 10^{-7}M$

$[H_3O^+]=\frac{10^{-14}}{1.55\times 10^{-7}}=0.64\times 10^{-7}M$

$pH=-log[H_3O^+]=-log[0.64\times 10^{-7}]=7$

B. $[H_3O^+]=9.43\times 10^{-9}M$

$[OH^-]=\frac{10^{-14}}{9.43\times 10^{-9}}=0.11\times 10^{-5}M$

$pH=-log[H_3O^+]=-log[9.43\times 10^{-9}]=8$

C. $[H_3O^+]=0.000775M$

$[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M$

$pH=-log[H_3O^+]=-log[0.000775]=3$

Thus solution B is basic.

4 0

4 years ago

Be able to describe the relationship between Freedom of Movement and phase change.

lisabon 2012 [21]

Ion knoe Wdym by “be able to describ’ so ima put it in my own words idr lol:)

if you talm bout some kentic energy or sum ok but other Dan dat ion knoe tbh

I can explain how transferring kinetic energy in and out of a substance can cause a change

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3 years ago

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Korolek [52]

Answer:

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Explanation:

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hjlf

Answer:

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