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iragen [17]
3 years ago
8

A _______ is a segment of DNA that contains the information necessary to express the inherited traits of an organism. A. protein

B. phenotype C. gene D. sex cell
Chemistry
1 answer:
Ilya [14]3 years ago
6 0

Answer:

"gene" is the segment of DNA containg the inheritance information.

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Is freshwater a mixture?
dem82 [27]

Answer:

No

Explanation:

A mixture is when two or more substances combine physically together. However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone. ... Therefore, water is not a mixture

7 0
3 years ago
Is the formation of acid rain an exothermic or endothermic reaction?
Monica [59]
It is an exothermic reaction
4 0
3 years ago
How many grams of HF are needed to react with 3.0 moles of Sn?
Flauer [41]

Answer:

120g

Explanation:

Step 1:

We'll begin by writing the balanced equation for the reaction.

Sn + 2HF —> SnF2 + H2

Step 2:

Determination of the number of mole HF needed to react with 3 moles of Sn.

From the balanced equation above,

1 mole of Sn and reacted with 2 moles of HF.

Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.

Step 3:

Conversion of 6 moles of HF to grams.

Number of mole HF = 6 moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn.

3 0
3 years ago
8 Fe + Sg → 8 Fes<br><br> How many grams of FeS is produced from 0.3 mol Sg?
frozen [14]

Answer:

Explanation:

Molar ratio for Sg : FeS = 1:8

If there are 0.3 moles for Sg

Therefore, 0.3 × 8 =2.4 moles of FeS

Mass = Moles/ Mr

Mr of FeS = 56+32=88

So mass = 2.4/88

Mass= 0.027g

6 0
3 years ago
What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C
Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = \frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\

Now use the molar ratio to find how many moles of NaOH would be required to neutralize 5.5537*10^{-3} mol\\ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

         1           :            2                  (we get this from the balanced equation)

5.5537*10^{-3} mol\\ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L

5 0
4 years ago
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