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iragen [17]
3 years ago
8

A _______ is a segment of DNA that contains the information necessary to express the inherited traits of an organism. A. protein

B. phenotype C. gene D. sex cell
Chemistry
1 answer:
Ilya [14]3 years ago
6 0

Answer:

"gene" is the segment of DNA containg the inheritance information.

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34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and wha
kolbaska11 [484]

Answer:

11 molecules of CH4.

23 atoms of C is the leftover.

Explanation:

Hello!

In this case, for the formation of methane:

C+2H_2\rightarrow CH_4

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2

Thus, the formed molecules of methane are computed below:

molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4

In such a way, the leftover of carbon atoms are:

atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C

Best regards!

4 0
3 years ago
Which common item is made
natima [27]

your answerneeds to be at least 20 characters long

7 0
3 years ago
Name three pure elements and three pure compounds​
VARVARA [1.3K]

Answer:

Pure elements:

Hydrogen(H)

Nitrogen(N)

Magnesium (Mg)

Pure Compounds:

Oxygen gas(O2)  

Water (H2O)  

Ammonia (NH3)

Explanation:

Hope it helps.Please mark me brainliest.^-^

5 0
3 years ago
What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?
Georgia [21]
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
4 0
3 years ago
Read 2 more answers
A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is t
Vladimir [108]

Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm                       P₂ = ? atm

V₁ = 7.74 L                           V₂ = 0.23 L

P₁V₁ = P₂V₂                                                      <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L)                       <----- Insert values

30.0312 = P₂(0.23 L)                                      <----- Simplify left side

131 = P₂                                                          <----- Divide both sides by 0.23

6 0
2 years ago
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